sole for x: - 3x - 5 < 10
Question
Updated 7/16/2014 3:01:48 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/16/2014 2:58:13 AM]
s
Original conversation
User: solve for x: -3x =5<10

User: sole for x: - 3x - 5 < 10

Weegy: C.) X <
btatkerson|Points 1108|

User: multiply; (x + 5) (x- 3)

Weegy: x > 2
ambrosio_09|Points 1040|

User: factor complelety: 12x^2y +18xy^2 +6x

User: evaluate: -9x^0

Weegy: The answer is 1. Anything to the power of 0 will equal 1. Try it on your calculator.
debnjerry|Points 28615|

User: Jocelyn has test scores of 80, 77, and 89 on her first tests in algebra. What must she score on her 4th test so she will have at least an 85 average?

Weegy: (80+77+89+x)/4 = 85, (246+x)/4 = 85, 246+x = 340, x = 91. Jocelyn will need to score 91 on her 4th test to have at least an 85 average.
debnjerry|Points 28615|

User: Subtract: (x^2 + 2x -4) - (x^2- 5x + 2)

Question
Updated 7/16/2014 3:01:48 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [7/16/2014 2:58:13 AM]
Rating
3
- 3x - 5 < 10
- 3x < 10 + 5
- 3x < 15
x > -5
Confirmed by andrewpallarca [7/16/2014 4:02:42 AM]
3
(x + 5) (x - 3) = x^2 - 3x + 5x - 15 = x^2 + 2x - 15

Confirmed by andrewpallarca [7/16/2014 4:02:55 AM]
3
12x^2y +18xy^2 + 6x = 6x(2xy + 3y^2 + 1)

Confirmed by andrewpallarca [7/16/2014 4:03:21 AM]
3
-9x^0 = -9
Confirmed by andrewpallarca [7/16/2014 4:03:34 AM]
3
(x^2 + 2x -4) - (x^2 - 5x + 2)
= x^2 + 2x -4 - x^2 + 5x - 2
= 7x - 6
Confirmed by andrewpallarca [7/16/2014 4:03:51 AM]

Questions asked by the same visitor
Solve by using PEMDAS: 4 + 3^2 / (6-4) User: solve by using PEMDAS: 8 x 2 +9 /3
Weegy: 6 x 3 + 10 ? 2 = 18+5 = 23 User: simplify: 6(y + 7) Weegy: 42y is the answer User: Multiply: (5xy^4) (2x^2y) Weegy: Do you have more to the equation? User: solve for x: -4x + 7 = 35 Weegy: The answer is x=-6,2. [ x^(2)-12=-4x Since -4x contains the variable to solve for, move it to the left-hand side of the equation by adding 4x to both sides. x^(2)-12+4x=0 Reorder the polynomial x^(2)-12+4x alphabetically from left to right, starting with the highest order term. x^(2)+4x-12=0 In this problem 6*-2=-12 and 6-2=4, so insert 6 as the right hand term of one factor and -2 as the right-hand term of the other factor. (x+6)(x-2)=0 Set each of the factors of the left-hand side of the equation equal to 0. x+6=0_x-2=0 Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides. x=-6_x-2=0 Set each of the factors of the left-hand side of the equation equal to 0. x=-6_x-2=0 Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides. x=-6_x=2 The complete solution is the set of the individual solutions. x=-6,2 ] User: solve for x: 4(x - 3) = 5(2x + 3) Weegy: 2x - 6 + 5x = 10x + 30 combine like terms 7x - 6 = 10x + 30 subtract 7x and 30 both sides -36 = 3x divide both sides by 3 -12 = x Checking : [ 2(x-3)+5x=5(2x+6) 2((-12)-3)+5(-12)=5(2(-12)+6) 2(-15) + 5(-12) = 5(-24+6) -30 - 60 = 5(-18) -90 = -90 - - - > true therefore, x = -12 ] User: degree of the polynomial Weegy: An example of a polynomial is 2x5 ? 5x3 ? 10x + 9. User: given the polynomial x^5 + x^3 - 5x^9 + 6x^2. what is the degree of the polynomial ? User: evaluate; x^2 + 13x + 15 when x= User: x^0 is equal to o Weegy: The answer is zero. The property is ... (More)
Question
Updated 6/28/2014 2:56:14 PM
8 x 2 +9 /3

= 16 + 3 = 19
(5xy^4) (2x^2y) = 10x^3y^5
4(x - 3) = 5(2x + 3);

4x - 12 = 10x + 15;

4x - 10x = 15 + 12;

-6x = 27;

x = -27/6 = -9/2
The degree of polynomial x^5 + x^3 - 5x^9 + 6x^2 is 9.
x^0 is NOT equal to 0.
Anything that is raised to 0 is always equal to 1.

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