Question and answer
What is the product of (n - 8)(n + 2)?
Question
Asked 11/17/2014 1:01:04 PM
Updated 12/4/2014 10:13:56 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [12/4/2014 10:13:41 PM]
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Original conversation
User: What is the product of (n - 8)(n + 2)?

Weegy: (a + 3)(a - 2)

= a^2 - 2a + 3a - 6;

= a^2 + a - 6


User: x2 + 13x + 36

Question
Asked 11/17/2014 1:01:04 PM
Updated 12/4/2014 10:13:56 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [12/4/2014 10:13:41 PM]
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8
(n - 8)(n + 2) = n^2 + 2n - 8n - 16 = n^2 - 6n - 16
Added 12/4/2014 10:13:35 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [12/4/2014 10:42:10 PM]
8
x^2 + 13x + 36 = (x + 4)(x + 9)
Added 12/4/2014 10:13:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [12/4/2014 10:42:39 PM]
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Questions asked by the same visitor
(x2 + 4x + 8)(2x - 1) User: (y + z)3
Question
Not Answered
Updated 11/17/2014 1:19:42 PM
2 Answers/Comments
(x^2 + 4x + 8)(2x - 1)

= 2x^3 - x^2 + 8x^2 - 4x + 16x - 8;

=2x^3 + 7x^2 + 12x - 8
Added 11/17/2014 1:16:37 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/17/2014 1:25:09 PM]
(y + z)^3

= (y + z)(y + z)(y + z)

= (y^2 + yz + yz + z^2)(y + z);

= (y^2 + 2yz + z^2)(y + z);

= y^3 + y^2z + 2y^2z + 2yz^2 + yz^2 + z^3;

= y^3 + 3y^2z + 3yz^2 + z^3
Added 11/17/2014 1:19:42 PM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [11/17/2014 1:26:24 PM]
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