Bandwidth = 1000 MB / 10 s = 100 MB/s.

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Bandwidth Formula: B = Data / Time Given: Data = 1000 MB Time = 10 s Solution: B = 1000 / 10 B = 100 MB/s Final Answer: Bandwidth = 100 MB/s

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Asked 44 days ago|6/8/2026 8:56:50 AM

Updated 44 days ago|6/8/2026 9:18:55 AM

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alfred123

Bandwidth Formula: B = Data / Time

Given:
Data = 1000 MB
Time = 10 s

Solution:
B = 1000 / 10
B = 100 MB/s

Final Answer: Bandwidth = 100 MB/s

Added 44 days ago|6/8/2026 9:18:51 AM

This answer has been confirmed as correct and helpful.

cruz30

[Deleted]

Added 44 days ago|6/8/2026 9:18:55 AM

This answer has been added to the Weegy Knowledgebase

Deleted by cruz30 [6/8/2026 9:18:59 AM]

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A 5 kg object accelerates at 3.2 m/s²; calculate force using F = ma = 5 × 3.2.

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Updated 44 days ago|6/8/2026 9:04:54 AM

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cruz30

Given: m = 5 kg, a = 3.2 m/s^2
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Added 44 days ago|6/8/2026 9:04:54 AM

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A projectile is launched at 40 m/s at 30°; calculate horizontal range using R = (v² sin 2 )/g = (40² × sin60°)/9.8.

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Updated 44 days ago|6/8/2026 9:11:35 AM

1 Answer/Comment

cruz30

Given:v=40m/s, =30°,g=9.8
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Added 44 days ago|6/8/2026 9:11:35 AM

This answer has been confirmed as correct and helpful.

Calculate mass of NaCl using mass = moles × molar mass = 0.75 × 58.5.

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Updated 44 days ago|6/8/2026 9:29:15 AM

1 Answer/Comment

cruz30

Given: mass = moles × molar mass
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Added 44 days ago|6/8/2026 9:29:15 AM

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Solve 3x² - 5x + 2 = 0 using quadratic formula x = [-b ± sqrt(b²-4ac)]/2a.

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Question

Updated 44 days ago|6/8/2026 9:28:55 AM

1 Answer/Comment

cruz30

Given: 3x^2 - 5x + 2 = 0
a = 3, b = -5, c = 2
x = [-b ± sqrt(b^2 - 4ac)] / 2a
= [5 ± sqrt((-5)^2 - 4(3)(2))] / 6
= [5 ± sqrt(25 - 24)] / 6
= [5 ± sqrt(1)] / 6
= [5 ± 1] / 6
x = (5 + 1)/6 = 6/6 = 1
x = (5 - 1)/6 = 4/6 = 2/3
Answer = x = 1, 2/3

Added 44 days ago|6/8/2026 9:28:55 AM

This answer has been confirmed as correct and helpful.

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