A triangular trough is 12m long,2m wide ate the top and 2m deep.If water flows in at the rate ot 12 cm(cube)/min.How fast the surface is rising when water is 1 meter deep?

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A triangular trough is 12m long,2m wide ate the top and 2m deep.If water flows in at the rate ot 12 cm(cube)/min.How fast the surface is rising when water is 1 meter deep?

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Asked 10/13/2008 8:41:02 AM

Updated 355 days ago|6/17/2025 8:24:58 AM

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User: A triangular trough is 12m long,2m wide ate the top and 2m deep.If water flows in at the rate ot 12 cm(cube)/min.How fast the surface is rising when water is 1 meter deep?

Weegy: I see that you are needing help with your math problem, I think that this may help you. [www.webmath.com/]

User: I need the answer:(

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Asked 10/13/2008 8:41:02 AM

Updated 355 days ago|6/17/2025 8:24:58 AM

1 Answer/Comment

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Volume of water: V = 6h²
Differentiate: dV/dt = 12h × dh/dt
Given: dV/dt = 0.000012, h = 1
Solve: 0.000012 = 12 × 1 × dh/dt - dh/dt = 0.000001 m/min
Answer: 0.000001 m/min or 0.001 mm/min

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Added 355 days ago|6/17/2025 8:24:58 AM

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