Question and answer
Solve the equation and solve the solution? 5(3z-1)-4(z+2)=6(z+1) The solution is z=?
5(3z-1)-4(z+2)=6(z+1), 11z-13=6z+6, 11z - 6 = 6 + 13, 5z = 19, The solution is z = 19/5
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Expert answered|andrewpallarca|Points 19331|
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Asked 2/11/2013 12:12:11 PM
Updated 6/19/2014 10:40:12 PM
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This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/19/2014 10:40:12 PM]
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Questions asked by the same visitor
2(x-2)-6=0 what is the equation x=
Weegy: 2(x-2)-6=0 ; 2x-4=6 ; 2x=10 ; x=10/2 ; x=5 (More)
Question
Expert Answered
Asked 2/11/2013 10:25:28 AM
0 Answers/Comments
Solove the solution. User: SOlve the solution z=what. 5(3z-1)-4(z+2)=6(z+1)
Question
Not Answered
Updated 4/26/2014 11:12:28 AM
1 Answer/Comment
5(3z-1)-4(z+2)=6(z+1)
15z - 5 - 4z - 8 = 6z + 6
11z - 13 = 6z + 6
11z - 6z = 6 + 13
5z = 19
z = 19/5
Added 4/26/2014 11:12:28 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/26/2014 1:37:52 PM]
-(z+7)+(6z+1)=-4(z+1). What is the soultion
Weegy: -6 + 5z = -4 + -4z (More)
Question
Expert Answered
Updated 2/12/2014 7:52:13 PM
1 Answer/Comment
-(z+7)+(6z+1)=-4(z+1)

-z - 7 + 6z + 1 = -4z - 4

5z - 6 = -4z - 4

5z + 4z = -4 + 6

9z = 2

z = 2/9

The solution is 2/9.
Added 2/12/2014 7:52:13 PM
This answer has been confirmed as correct and helpful.
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