Add the following polynomials: (x^2 – 4x – 3) + (x^2 – 3x – 7) a. -2x^2-7x-10 b. 2x^2+7x-10 c. 2x^2-7x-10 d. 2x^2-7x+10
(x2 – 4x – 3) + (x2 – 3x – 7) = x^2 - 4x - 3 + x^2 - 3x - 7 = 2x^2 - 7x - 10
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Question
Updated 4/6/2014 3:03:40 PM
Confirmed by andrewpallarca [4/6/2014 3:03:40 PM]
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Add the following polynomials: (4x^2 + 2x – 3) + (x^2 – x + 9) a. 5x^2+x+6 b. 4x^2+x+6 c. 5x^2+x+5 d. 4x^2+x+5
Weegy: 7x+9=16 so x=1 (More)
Question
Updated 5/29/2014 9:38:24 PM
(4x^2 + 2x – 3) + (x^2 – x + 9)
= 4x^2 + 2x – 3 + x^2 – x + 9
= (4x^2 + x^2) + (2x - x) + (9 - 3)
= 5x^2 + x + 6
Confirmed by jeifunk [5/29/2014 9:46:58 PM]
Add the following polynomials: (4x^2 + 2x – 3) + (x^2 – x + 9) a. 5x^2+x+6 b. 4x^2+x+6 c. 5x^2+x+5 d. 4x^2+x+5
Weegy: the product (x + 1)(x + 4) will be- (x + 1)(x + 4)= x^2+4x+x+4 = x^2+5x+4 So the answer will be option A- x^2+5x+4 User: Add the following polynomials: (4x^2 + 2x – 3) + (x^2 – x + 9) a. 5x^2+x+6 b. 4x^2+x+6 c. 5x^2+x+5 d. 4x^2+x+5 Weegy: the product (x + 1)(x + 4) will be- (x + 1)(x + 4)= x^2+4x+x+4 = x^2+5x+4 So the answer will be option A- x^2+5x+4 (More)
Question
Updated 8/1/2014 12:53:17 PM
(4x^2 + 2x – 3) + (x^2 – x + 9)
= 5x^2 + x + 6
Add the following polynomials: (x^2 – x + 7) + (x^2 + 3x + 1) a. 2x^2+2x-8 b. 2x^2+2x+8 c. 2x^2-2x+8 d. -2x^2+2x+8
Weegy: (x^2 – x + 7) + (x^2 + 3x + 1) = b. 2x^2+2x+8 (More)
Question
Updated 5/31/2014 2:58:24 PM
Add the following polynomials: (7x^2 + x + 13) + (2x^2 – 5x + 10) a. -9x^2-4x+23 b. 9x^2+4x+23 c. 9x^2-4x-23 d. 9x^2-4x+23
Weegy: (7x^2 + x + 13) + (2x^2 – 5x + 10) = d. 9x^2-4x+23 (More)
Question
Updated 5/31/2014 2:59:20 PM
Add the following polynomials: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) a. -5x^2-7x+5 b. 5x^2-7x+5 c. -5x^2+7x+5 d. 5x^2-7x-5
Weegy: (–3x^2 + 3x + 3) + (–2x^2 – 10x + 2) = -5x^2 - 7x + 5 (More)
Question
Updated 8/1/2014 12:50:54 PM
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