3
h = 6 m, g = 9.8 m/s²
v = sqrt (2*g*h) = sqrt (2*9.8*6) = sqrt117.6 = 10.84 m/s
Added 37 days ago|1/29/2026 6:32:20 AM
This answer has been confirmed as correct and helpful.
3
v² = 2gh
v = sqrt(2gh)
Substitute the given values:
v = sqrt(2 * 9.8 m/s² * 6 m)
v = sqrt(117.6 m²/s²)
v 10.84 m/s
Therefore, the speed of the body at the bottom of the incline is approximately 10.84 m/s.
Added 37 days ago|1/29/2026 6:32:51 AM
This answer has been confirmed as correct and helpful.
