Solve the system of linear equations below. x + y = 4 2x + 3y = 0
x + y = 4 2x + 3y = 0 x = -y + 4 2(-y + 4) + 3y = 0 -2y + 8 + 3y = 0 y + 8 = 0 y = -8 x - 8 = 4 x = 4 + 8 x = 12 Solution set: (12, -8)
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Question
Updated 12/16/2015 10:52:49 PM
Edited by Andrew. [12/16/2015 10:52:43 PM]
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8
x + y = 4
2x + 3y = 0
x = -y + 4
2(-y + 4) + 3y = 0
-2y + 8 + 3y = 0
y + 8 = 0
y = -8
x - 8 = 4
x = 4 + 8
x = 12
Solution set: (12, -8)

Questions asked by the same visitor
x + y = 4 2x + 3y = 0
Weegy: [ ] User: Solve the system of linear equations below. x + y = 4 2x + 3y = 0 Weegy: FOIL (First Outside Inside Last) = 2x(2x) + 2x(-3y) + (-3y)(2x) + (-3y)(-3y) = 4x^2 + (-6xy) + (-6xy) + (9y^2) = 4x^2 - 12xy + 9y^2 (More)
Question
Updated 1/2/2015 2:48:43 PM
The solution set for x + y = 4, 2x + 3y = 0 is (x = 12, y = -8).
(x + y = 4) * (-2);
-2x - 2y = -8;
(-2x - 2y = -8) + (2x + 3y = 0);
y = -8;
x - 8 = 4;
x = 4 + 8;
x = 12
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