a sample of heater is heated with an immersion heater. the temperature of the water goes from 10.0 to 25.0c after absorbing 20,000j . 287.65 grams is the mass of the water heated.
Solution

Q = mc T

Where:
Q = Heat energy absorbed by the water (in joules)
m = Mass of the water (in kilograms)
c = Specific heat capacity of water (assumed to be 4.18 J/g·°C or 4.18 J/g·K)
T = Change in temperature (in °C or K)

Given:
Q = 20,000 J
T = 25.0°C - 10.0°C = 15.0°C

First, let's convert the heat energy from joules to calories (1 calorie = 4.18 joules):
Q = 20,000 J * (1 cal / 4.18 J) 4,784 cal

Now, rearrange the formula to solve for mass (m):
m = Q / (c T)

Plugging in the values:
m = 4,784 cal / (4.18 J/g·°C * 15.0°C)

Simplifying:
m 287.65 grams