a sample of heater is heated with an immersion heater. the temperature of the water goes from 10.0 to 25.0c after absorbing 20,000j . what is th mass of the water heated?

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Asked 10/4/2008 11:40:20 AM

Updated 339 days ago|7/10/2023 12:21:43 AM

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a sample of heater is heated with an immersion heater. the temperature of the water goes from 10.0 to 25.0c after absorbing 20,000j . 287.65 grams is the mass of the water heated.

Solution

Q = mc T

Where:

Q = Heat energy absorbed by the water (in joules)

m = Mass of the water (in kilograms)

c = Specific heat capacity of water (assumed to be 4.18 J/g·°C or 4.18 J/g·K)

T = Change in temperature (in °C or K)

Given:

Q = 20,000 J

T = 25.0°C - 10.0°C = 15.0°C

First, let's convert the heat energy from joules to calories (1 calorie = 4.18 joules):

Q = 20,000 J * (1 cal / 4.18 J) 4,784 cal

Now, rearrange the formula to solve for mass (m):

m = Q / (c T)

Plugging in the values:

m = 4,784 cal / (4.18 J/g·°C * 15.0°C)

Simplifying:

m 287.65 grams

Solution

Q = mc T

Where:

Q = Heat energy absorbed by the water (in joules)

m = Mass of the water (in kilograms)

c = Specific heat capacity of water (assumed to be 4.18 J/g·°C or 4.18 J/g·K)

T = Change in temperature (in °C or K)

Given:

Q = 20,000 J

T = 25.0°C - 10.0°C = 15.0°C

First, let's convert the heat energy from joules to calories (1 calorie = 4.18 joules):

Q = 20,000 J * (1 cal / 4.18 J) 4,784 cal

Now, rearrange the formula to solve for mass (m):

m = Q / (c T)

Plugging in the values:

m = 4,784 cal / (4.18 J/g·°C * 15.0°C)

Simplifying:

m 287.65 grams

Added 339 days ago|7/10/2023 12:21:43 AM

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