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Use the distributive property to multiply 7x(a + c).
Question
Asked 6/1/2009 2:38:02 PM
Updated 7/25/2014 3:02:21 AM
1 Answer/Comment
Flagged by alfred123 [7/25/2014 3:01:58 AM]
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User: Use the distributive property to multiply 7x(a + c).

Question
Asked 6/1/2009 2:38:02 PM
Updated 7/25/2014 3:02:21 AM
1 Answer/Comment
Flagged by alfred123 [7/25/2014 3:01:58 AM]
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8
7x(a + c) = 7ax + 7cx
Added 7/25/2014 3:02:21 AM
This answer has been confirmed as correct and helpful.
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1/6 · a = 1
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Updated 9/1/2014 7:22:39 AM
1 Answer/Comment
1/6 · a = 1;
1/6a = 1;
a = 6 * 1;
a = 6
Added 9/1/2014 7:22:39 AM
This answer has been confirmed as correct and helpful.
5/6 · k = 10
Weegy: K= 5 User: ur wrong (More)
Question
Expert Answered
Updated 9/1/2014 7:21:10 AM
1 Answer/Comment
5/6 · k = 10;
5/6k = 10;
k = (10)/(5/6);
k = 60/5;
k = 12
Added 9/1/2014 7:21:09 AM
This answer has been confirmed as correct and helpful.
5/6 · k = 10
Weegy: (6/5)*(5/6)k=10*(6/5), 1*k=60/5, k=12 User: 7/10 · a = 21 Weegy: (10/7)*(7/10)a=21*(10/7), 1*a=210/7, a=30 (More)
Question
Expert Answered
Updated 9/1/2014 7:21:52 AM
0 Answers/Comments
2x = 6 wat does x =
Weegy: -3 (More)
Question
Expert Answered
Updated 288 days ago|8/29/2020 2:14:29 PM
2 Answers/Comments
2x = 6; x = 3

Explanation:
2x = 6
To find X divide both sides of the equation by the coefficient of X (2)
2x/2 = 6/2
x = 3
Added 288 days ago|8/29/2020 2:11:40 PM
This answer has been confirmed as correct and helpful.
2x = 6 wat does x =?
According to the question :-
2x = 6
x = 3
Added 288 days ago|8/29/2020 2:14:29 PM
2x = 6 x=
Weegy: 2x=6x is not something i can work with. is there more to the equation? Otherwise it is undefined. User: this is all it gives me Solve and check the equation, but only type in your answer as variable = solution. 2x = 6 x = (More)
Question
Expert Answered
Updated 288 days ago|8/29/2020 2:13:00 PM
1 Answer/Comment
2x = 6; x = 3

Explanation:
2x = 6
To find x divide both sides of the equation by the coefficient of x (2)
2x/2 = 6/2
x = 3
Added 288 days ago|8/29/2020 2:13:00 PM
This answer has been confirmed as correct and helpful.
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