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Find the product. 3y2z(2y2z + 4yz - y + z)
Question
Asked 6/6/2013 4:47:25 PM
Updated 9/26/2014 9:21:27 PM
1 Answer/Comment
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Flagged by janezeshun [9/26/2014 9:19:38 PM]
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User: Find the product. 3y2z(2y2z + 4yz - y + z)

Weegy: y = 1, z = 3
RinatisDinoro|Points 270|

Question
Asked 6/6/2013 4:47:25 PM
Updated 9/26/2014 9:21:27 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by janezeshun [9/26/2014 9:19:38 PM]
New answers
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8
3y^2z(2y^2z + 4yz - y + z)
= 3y^2z*2y^2z + 3y^2z*4yz - 3y^2z*y + 3y^2z*z
= 6y^4z^2 + 12y^3z^2 -3y^3z +3y^2z^2
Added 9/26/2014 9:21:27 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [9/26/2014 11:43:36 PM], Rated good by jeifunk
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Questions asked by the same visitor
Find the product. (6a + b)2
Weegy: 12z + 2b User: Simplify b(a + b) - a(a - b). Weegy: b(a + b) - a(a - b) is equal to n^2-a^2+2ab or -a^2+2ab+b^2. SOLUTION: b(a + b) - a(a - b) ab+b^2-a^2+ab b^2-a^2+ab+ab n^2-a^2+2ab or -a^2+2ab+b^2 User: Find the quotient. y9 ÷ y3 Weegy: = y3 User: Find the quotient. (35n3 - 30n2 + 25n) ÷ (-5n) Weegy: the quotient is -7n2 + 6n - 5. User: Find the product. (-d + 4)(-d - 4) Weegy: -d square + 16 User: Given: X = r + 2, Y = 2r - 9, and Z = r2 + 17r + 30. Simplify [X · Y - Z] ÷ X. Weegy: (r+2)(2r-9)-(r^(2)+17r+30)/(r+2)... For a polynomial of the form x^(2)+bx+c, find two factors of c (30) that add up to b (17). [ In this problem 15*2=30 and 15+2=17, so insert 15 as the right hand term of one factor and 2 as the right-hand term of the other factor. (r+2)(2r-9)-((r+15)(r+2))/(r+2)... Reduce the expression by canceling out the common factor of (r+2) from the numerator and denominator. (r+2)(2r-9)-((r+15) (r+2) )/( (r+2) )... Reduce the expression by canceling out the common factor of (r+2) from the numerator and denominator. (r+2)(2r-9)-(r+15) Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group. (r*2r+r*-9+2*2r+2*-9)-(r+15)... Simplify the FOIL expression by multiplying and combining all like terms. (2r^(2)-5r-18)-(r+15)... Multiply -1 by each term inside the parentheses. (2r^(2)-5r-18)+-r-15... Since -5r and -r are like terms, subtract r from -5r to get -6r. 2r^(2)-6r-18-15... Subtract 15 from -18 to get -33. 2r^(2)-6r-33 is the answer. ] User: Find the product. (7q - 5)(7q + 5) Weegy: 49q^2-25 is the product. User: Find the product. 3y2z(2y2z + 4yz - y + z) Weegy: y = 1, z = 3 (More)
Question
Updated 6/27/2014 6:59:24 AM
4 Answers/Comments
(6a + b)2 = 12a+2b
Added 6/27/2014 6:54:45 AM
This answer has been confirmed as correct and helpful.
The quotient of y9 ÷ y3 = y6
Added 6/27/2014 6:55:56 AM
This answer has been confirmed as correct and helpful.
(-d + 4)(-d - 4)
=d^2+4d 4d 16
=d^2-16
Added 6/27/2014 6:56:57 AM
This answer has been confirmed as correct and helpful.
3y^2z(2y^2z+4yz-y+z) = 6y^4z^2+12y^3z^2-3y^3z+3y^2z^2
Added 6/27/2014 6:59:17 AM
This answer has been confirmed as correct and helpful.
Multiply (6z2 - 4z + 1)(8 - 3z).
Weegy: 48z2 - 18z3 -32z + 12z2 + 8 -3z= -18z3 + 60z2 -35z + 8 User: Find the product. (6a + b)2 Weegy: the product. (6a + b)2 answer: 12z + 2b (More)
Question
Expert Answered
Updated 10/16/2014 4:14:25 AM
1 Answer/Comment
(6a + b)^2
= 36a^2 + 12ab + b^2
Added 10/16/2014 4:14:25 AM
This answer has been confirmed as correct and helpful.
Confirmed by sujaysen [10/16/2014 9:26:02 AM]
Find the product. (7q - 5)(7q + 5)
Weegy: (7q - 5)(7q + 5) = 49q^2 + 35q - 35q - 25 = 49q^2 - 25 User: Find the product. (2p + 7)(3p - 9) (More)
Question
Updated 8/16/2016 9:01:15 AM
1 Answer/Comment
(2p + 7)(3p - 9)
= 6p^2 - 18p + 21p - 63
= 6p^2 + 3p - 63
Added 8/16/2016 9:01:15 AM
This answer has been confirmed as correct and helpful.
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