solve for x (x – 4 )(3x + 2) = 0
Question
Updated 6/4/2014 8:36:37 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [6/4/2014 8:34:32 AM]
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Original conversation
User: solve for x (x – 4 )(3x + 2) = 0

Weegy: (x-4) (3 x+2) = 3 x^2- 10 x - 8, solving for x gives us: x1 = -2/3, x2 = 4. Source:
eturker|Points 1440|

User: Solve for X X2 – 2x – 35 = 0

User: X2 – 2x – 35 = 0

User: X^2 – 2x – 35 = 0

Weegy: +1 = 2/3
emosara|Points 1294|

User: X^2 + 20 = -9x

User: X^2 – 16 = 0

Weegy: {x | x 0}
japs2310qa|Points 1120|

Question
Updated 6/4/2014 8:36:37 AM
This conversation has been flagged as incorrect.
Flagged by yeswey [6/4/2014 8:34:32 AM]
Rating
8
x (x – 4 )(3x + 2) = 0
x = 0, x - 4 = 0 or 3x + 2 = 0
x = 0, x = 4, or x = -2/3
Confirmed by andrewpallarca [6/4/2014 12:28:58 PM]
8
x^2 – 2x – 35 = 0
(x + 5)(x - 7) = 0
x + 5 = 0 or x - 7 = 0
x = -5 or x = 7
Confirmed by andrewpallarca [6/4/2014 12:29:25 PM]
8
x^2 + 20 = -9x
x^2 + 9x + 20 = 0
(x + 4)(x + 5) = 0
x = -4 or x = -5
Confirmed by andrewpallarca [6/4/2014 12:29:56 PM]
8
x^2 – 16 = 0
(x + 4)(x - 4) = 0
x = -4 or x = 4
Confirmed by andrewpallarca [6/4/2014 12:30:27 PM]

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