A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. How tall is the ledge? A. 1,254.4 meters B. 39.2 meters C. 78.4 meters D. 313.6 meters
A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. d=(1/2)at^2 ; d = 1/2 * 9.8 * 8^2 =; d = 313.6m
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Asked 2/7/2019 4:02:47 PM
Updated 4/5/2021 11:47:39 AM
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A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. d=(1/2)at^2 ; d = 1/2 * 9.8 * 8^2 =;
d = 313.6m
Added 4/5/2021 11:47:39 AM
This answer has been confirmed as correct and helpful.

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A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. How tall is the ledge? A. 1,254.4 meters B. 39.2 meters C. 78.4 meters D. 313.6 meters
Weegy: A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. How tall is the ledge? 313.6 meters (More)
Question
Updated 57 days ago|2/16/2024 4:00:56 AM
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Added 57 days ago|2/16/2024 4:00:56 AM
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Deleted by TwinPack [2/16/2024 4:01:12 AM]
A stone falls from a ledge and takes 8 seconds to hit the ground. The stone has an original velocity of 0 m/s. d=(1/2)at^2 ; d = 1/2 * 9.8 * 8^2 =; 313.6m.
Added 57 days ago|2/16/2024 4:01:33 AM
This answer has been confirmed as correct and helpful.
A piston above a liquid in a closed container has an area of 1 m² the piston carries a load of 350 kg what will be the external pressure on the upper surface of a liquid
Question
Updated 11/27/2020 9:22:35 PM
A piston above a liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. 3.43 kPa will be the external pressure on the upper surface of the liquid. Solution: The weight of the load is (mass) x (gravity) = (350 kg) x (9.8 m/s²) = 3,430 newtons. (3,430 newtons) / (1 m²) = 3,430 pascals = 3.43 kPa.
Added 11/27/2020 9:22:35 PM
This answer has been confirmed as correct and helpful.
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