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A 0.6 kg mass moves in a horizontal circle of radius 0.4 m at 6 m/s. Determine the centripetal force.
m = 0.6 kg, r = 0.4 m, v = 6 m/s Centripetal force: F = m*v²/r = 0.6*6² / 0.4 = 0.6*36 / 0.4 = 21.6 / 0.4 = 54 N
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Asked 37 days ago|1/29/2026 5:57:08 AM
Updated 37 days ago|1/29/2026 6:34:20 AM
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m = 0.6 kg, r = 0.4 m, v = 6 m/s
Centripetal force: F = m*v²/r = 0.6*6² / 0.4 = 0.6*36 / 0.4 = 21.6 / 0.4 = 54 N
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Added 37 days ago|1/29/2026 6:34:08 AM
This answer has been confirmed as correct and helpful.
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F_c = (0.6 kg * (6 m/s)^2) / 0.4 m = (0.6 kg * 36 m2/s2) / 0.4 m = 21.6 N / 0.4 = 54 N.

Therefore, the centripetal force is 54 N.
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Added 37 days ago|1/29/2026 6:34:20 AM
This answer has been confirmed as correct and helpful.
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