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4x^-2/y^-8
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Asked 3/22/2012 9:34:00 AM
Updated 7/8/2014 12:21:46 AM
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Flagged by andrewpallarca [7/8/2014 12:21:46 AM]
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User: 4x^-2/y^-8

Weegy: Exact Y = 3(X+16)/4 Approximate Y = 0.75 (X+16.)
Lavanda|Points 37|

Question
Asked 3/22/2012 9:34:00 AM
Updated 7/8/2014 12:21:46 AM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by andrewpallarca [7/8/2014 12:21:46 AM]
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4x^-2/y^-8

= (4/x^2)/(1/y^8)

= 4y^8/x^2
Added 7/8/2014 12:21:44 AM
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