Question and answer
(5/2)+(1/5)=(1/x)
Question
Asked 11/3/2013 5:50:25 PM
Updated 4/7/2014 8:30:11 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Get an answer
Original conversation
User: (5/2)+(1/5)=(1/x)

Weegy: x+(4)/(x)+2=x+(1)/(x)+5 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is x. [ Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. x+(4)/(x)+2=x*(x)/(x)+(1)/(x)+5*(x)/(x) Multiply x by x to get x^(2). x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+5*(x)/(x) Multiply 5 by x to get 5x. x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+(5x)/(x) Combine the numerators of all expressions that have common denominators. x+(4)/(x)+2=(x^(2)+1+5x)/(x) Reorder the polynomial x^(2)+1+5x alphabetically from left to right, starting with the highest order term. x+(4)/(x)+2=(x^(2)+5x+1)/(x) Find the LCD (least common denominator) of x+(4)/(x)+2+((x^(2)+5x+1))/(x). Least common denominator: x Multiply each term in the equation by x in order to remove all the denominators from the equation. x*x+(4)/(x)*x+2*x=(x^(2)+5x+1)/(x)*x Cancel the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+(4)/( x )* x +2*x=(x^(2)+5x+1)/(x)*x Reduce the expression by removing the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply x by x to get x^(2). x^(2)+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply 4 by 1 to get 4. x^(2)+4+2*x=(x^(2)+5x+1)/(x)*x Multiply 2 by x to get 2x. x^(2)+4+2x=(x^(2)+5x+1)/(x)*x Reorder the polynomial x^(2)+4+2x alphabetically from left to right, starting with the highest order term. x^(2)+2x+4=(x^(2)+5x+1)/(x)*x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1)/( x )* x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1) Remove the parentheses around the expression x^(2)+5x+1. x^(2)+2x+4=x^(2)+5x+1 Since x^(2) contains the variable to solve for, move it to the left-hand side of the equation by subtracting x^(2) from both sides. x^(2)+2x+4-x^(2)=5x+1 Since 5x contains the variable to solve for, move it to the left-hand side of the ]
thederby|Points 1530|

Question
Asked 11/3/2013 5:50:25 PM
Updated 4/7/2014 8:30:11 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
New answers
Rating
3
(5/2) + (1/5) = (1/x)
(25/10) + (2/10) = (1/x)
27/10 = 1/x
x = 10/27
Added 4/7/2014 8:30:11 PM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [4/7/2014 8:32:11 PM]
Comments

There are no comments.

Add an answer or comment
Log in or sign up first.
27,379,314
questions answered
GET
Answers.
GET THE APP.
weegy*
*
Get answers from Weegy and a team of really smart live experts.
Popular Conversations
Government _____ and all of the rules associated with driving anger ...
Weegy: Anger is an emotion characterized by antagonism toward someone or something you feel has deliberately done you ...
9/23/2018 4:41:28 PM| 2 Answers
what is medical control
Weegy: Medical billing is basically an interactive process between registered medical institutions, medical ...
9/19/2018 1:10:10 AM| 2 Answers
Irrational number
Weegy: Integers are NEVER irrational numbers. User: Integers
9/20/2018 7:22:35 AM| 2 Answers
Mongol conquerors founded which Chinese Dynasty?
Weegy: The Mongols, or Mongolic peoples, are a Central and Northern Asian (Inner Asia) ethno-linguistic group. User: ...
9/20/2018 8:28:58 AM| 2 Answers
S
L
Points 1313 [Total 1624] Ratings 16 Comments 1153 Invitations 0 Online
S
R
L
R
P
R
P
R
R
R
R
Points 493 [Total 1377] Ratings 4 Comments 363 Invitations 9 Offline
S
L
R
P
R
P
R
P
R
Points 452 [Total 1227] Ratings 3 Comments 392 Invitations 3 Offline
S
L
P
P
P
Points 363 [Total 1239] Ratings 0 Comments 363 Invitations 0 Offline
S
L
R
Points 77 [Total 194] Ratings 0 Comments 77 Invitations 0 Offline
S
Points 23 [Total 23] Ratings 0 Comments 23 Invitations 0 Offline
S
Points 10 [Total 10] Ratings 0 Comments 0 Invitations 1 Offline
S
L
1
R
Points 2 [Total 1453] Ratings 0 Comments 2 Invitations 0 Offline
S
Points 2 [Total 2] Ratings 0 Comments 2 Invitations 0 Offline
S
Points 1 [Total 1] Ratings 0 Comments 1 Invitations 0 Offline
* Excludes moderators and previous
winners (Include)
Home | Contact | Blog | About | Terms | Privacy | © Purple Inc.