(5/2)+(1/5)=(1/x)
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Updated 4/7/2014 8:30:11 PM
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User: (5/2)+(1/5)=(1/x)

Weegy: x+(4)/(x)+2=x+(1)/(x)+5 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is x. [ Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. x+(4)/(x)+2=x*(x)/(x)+(1)/(x)+5*(x)/(x) Multiply x by x to get x^(2). x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+5*(x)/(x) Multiply 5 by x to get 5x. x+(4)/(x)+2=(x^(2))/(x)+(1)/(x)+(5x)/(x) Combine the numerators of all expressions that have common denominators. x+(4)/(x)+2=(x^(2)+1+5x)/(x) Reorder the polynomial x^(2)+1+5x alphabetically from left to right, starting with the highest order term. x+(4)/(x)+2=(x^(2)+5x+1)/(x) Find the LCD (least common denominator) of x+(4)/(x)+2+((x^(2)+5x+1))/(x). Least common denominator: x Multiply each term in the equation by x in order to remove all the denominators from the equation. x*x+(4)/(x)*x+2*x=(x^(2)+5x+1)/(x)*x Cancel the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+(4)/( x )* x +2*x=(x^(2)+5x+1)/(x)*x Reduce the expression by removing the common factor of x in the denominator of the first term (4)/(x) and the second term x. x*x+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply x by x to get x^(2). x^(2)+4*1+2*x=(x^(2)+5x+1)/(x)*x Multiply 4 by 1 to get 4. x^(2)+4+2*x=(x^(2)+5x+1)/(x)*x Multiply 2 by x to get 2x. x^(2)+4+2x=(x^(2)+5x+1)/(x)*x Reorder the polynomial x^(2)+4+2x alphabetically from left to right, starting with the highest order term. x^(2)+2x+4=(x^(2)+5x+1)/(x)*x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1)/( x )* x Cancel the common factor of x from the denominator of the first expression and the numerator of the second expression. x^(2)+2x+4=(x^(2)+5x+1) Remove the parentheses around the expression x^(2)+5x+1. x^(2)+2x+4=x^(2)+5x+1 Since x^(2) contains the variable to solve for, move it to the left-hand side of the equation by subtracting x^(2) from both sides. x^(2)+2x+4-x^(2)=5x+1 Since 5x contains the variable to solve for, move it to the left-hand side of the ]
thederby|Points 1530|

Question
Updated 4/7/2014 8:30:11 PM
This conversation has been flagged as incorrect.
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(5/2) + (1/5) = (1/x)
(25/10) + (2/10) = (1/x)
27/10 = 1/x
x = 10/27
Confirmed by yumdrea [4/7/2014 8:32:11 PM]

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