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Solve the system of equations. 6x + 2y = 10 and -6x - 2y = 12: (A) (0, 5) (B) (-1, 8) (C) (2, -1) (D) no solution (E) infinitely many solutions
Question|Asked by renaryoko
Asked 4/2/2014 3:46:36 AM
Updated 4/22/2014 7:38:34 PM
1 Answer/Comment
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Flagged by yeswey [4/22/2014 7:38:34 PM]
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User: Solve the system of equations. 6x + 2y = 10 and -6x - 2y = 12: (A) (0, 5) (B) (-1, 8) (C) (2, -1) (D) no solution (E) infinitely many solutions

Weegy: Please clarify your question.Thank you.
dclark|Points 60|

Question|Asked by renaryoko
Asked 4/2/2014 3:46:36 AM
Updated 4/22/2014 7:38:34 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [4/22/2014 7:38:34 PM]
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6x + 2y = 10;
-6x - 2y = 12
Adding up the above equations we have:
0 = 22 which is not true.
Therefore, there is NO SOLUTION for the system of equations 6x + 2y = 10 and -6x - 2y = 12.
Added 4/22/2014 7:38:16 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/23/2014 1:25:47 PM]
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Questions asked by renaryoko
The ordered pair (-1, -1) is a solution of the system -4x + 2y = 2 and x + y = -2. (A) True (B) false
Weegy: True User: How many solutions exist for the system y = 2x + 5 and y = -0.2x - 4? (A) one solution (B) no solution (C) infinitely many solutions Weegy: solutions exist for the system y = 2x + 5 and y = -0.2x - 4: (C) infinitely many solutions User: How many solutions exist for the system, x + y = 1 and y = -x + 1? (A) one solution (B) no solution (C) infinitely many solutions Weegy: b. one solution (More)
Question|Asked by renaryoko
Expert Answered
Updated 4/22/2014 7:51:34 PM
3 Answers/Comments
y = 2x + 5
y = -0.2x - 4
Replace y in the second equation we have:
2x + 5 = -0.2x - 4
2x + 0.2x = -4 - 5
2.2x = -9
x = -9/2.2 = -90/22 = -45/11
y = -0.2(-9/2.2) - 4 = 9/11 - 4 = - 35/11
There is only ONE SOLUTION for the system of equations y = 2x + 5 and y = -0.2x - 4.
Added 4/22/2014 7:48:05 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/22/2014 7:57:21 PM]
x + y = 1
y = -x + 1
Replace y in the first equation we have:
x + (-x + 1) = 1
x - x + 1 = 1
0 = 0
therefore there are infinitely many solutions for the system x + y = 1 and y = -x + 1.
Added 4/22/2014 7:51:34 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [4/22/2014 7:57:28 PM]
Solve the system. y = -1/3 x + 2 and x + 3y = 3: (A)(0, 1) (B) (1, 0) (C) (3, 1/3) (D) (3/2, 0) (E) no solution
Question|Asked by renaryoko
Not Answered
Updated 4/22/2014 1:52:50 PM
1 Answer/Comment
y = -1/3 x + 2;
3y = -x + 6;
x + 3y = 6;- >(1);

x + 3y = 3;->(2);

There is no solution for the above equations.

Added 4/22/2014 1:52:50 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [4/22/2014 1:56:55 PM]
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