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How do I show the limit of sin(ax)/bx =a/b as x approaches 0
While there is a much better explanation in Wikipedia it can't be pasted into Yahoo Answers. [ Basically if there are two differentiable functions f(x) and g(x) such that f(x) and g(x) approach 0 as x approaches something then: limit (f(x) / g(x)) = x->something limit (f '(x) / g '(x)) x-> that same something There are circumstances when this is not applicable but they are relatively rare and they don't apply for your problem. So the limit for which you are searching is found as follows: d(sin(ax))/dx = a * cos(ax) d(bx)/dx = b limit (a * cos(ax)) / b = ((a * 1) / (b)) = (a / b).....
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Expert answered|jeifunk|Points 6457|
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Asked 9/13/2012 6:08:46 PM
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