Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20.
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Updated 10/9/2018 5:52:33 PM
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User: Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20.

Weegy: 80 = 3y + 2y + 4 + 1
Score .8334

Question
Updated 10/9/2018 5:52:33 PM
This conversation has been flagged as incorrect.
Flagged by Ishm [10/9/2018 5:52:33 PM]
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2x + 3y = 40 and –2x + 2y = 20 ; Add both equation 2x + 3y + (–2x + 2y) = 40 + 20 ;2x + 3y –2x + 2y = 60 ; 5y = 60 ; y = 60/5 ; y = 12 ; 2x + 3y = 40 ; 2x + 3 *12 = 40 ; 2x = 40 - 36 ; 2x = 4 ; x = 4/2 = 2 ; x = 2 ; y = 12

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John must have at least 289 test points to pass his math class. He already has test scores of 72, 78, and 70. 72 + 78 + 70 + x = 289 will tell him at least how many more points he needs to pass the class.

Solution:

72 + 78 + 70 + x = 289

220 + x = 289

x = 289 - 220

x = 69 more points he needs to pass the class.
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Solve the following equation: 6y – 20 = 2y – 4.
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