Solve the system of equations 2x + 3y = 40 and –2x + 2y = 20.

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Asked 10/9/2018 12:02:02 PM

Updated 10/9/2018 5:52:33 PM

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Question

Asked 10/9/2018 12:02:02 PM

Updated 10/9/2018 5:52:33 PM

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This conversation has been flagged as incorrect.

Flagged by Ishm [10/9/2018 5:52:33 PM]

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2x + 3y = 40 and –2x + 2y = 20 ; Add both equation 2x + 3y + (–2x + 2y) = 40 + 20 ;2x + 3y –2x + 2y = 60 ; 5y = 60 ; y = 60/5 ; y = 12 ; 2x + 3y = 40 ; 2x + 3 *12 = 40 ; 2x = 40 - 36 ; 2x = 4 ; x = 4/2 = 2 ; x = 2 ; y = 12

Added 10/9/2018 5:52:31 PM

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Updated 290 days ago|10/10/2020 5:34:51 PM

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= 4 + 2 ? 3
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Updated 344 days ago|8/17/2020 2:20:47 PM

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John must have at least 289 test points to pass his math class. He already has test scores of 72, 78, and 70. 72 + 78 + 70 + x = 289 will tell him at least how many more points he needs to pass the class.

Solution:

72 + 78 + 70 + x = 289

220 + x = 289

x = 289 - 220

x = 69 more points he needs to pass the class.

Solution:

72 + 78 + 70 + x = 289

220 + x = 289

x = 289 - 220

x = 69 more points he needs to pass the class.

Added 344 days ago|8/17/2020 2:20:47 PM

This answer has been confirmed as correct and helpful.

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Added 310 days ago|9/20/2020 7:45:30 PM

This answer has been confirmed as correct and helpful.

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Updated 10/9/2018 12:20:54 PM

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