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determine the molecular formula of a compound of 0.44g of nitrogen and 1.1.12g of oxygen and a molecular mass of 92.0g
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Asked 9/11/2008 9:51:48 AM
Updated 6 days ago|4/11/2025 9:47:34 AM
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User: determine the molecular formula of a compound of 0.44g of nitrogen and 1.1.12g of oxygen and a molecular mass of 92.0g

Weegy: one moment

Question
Asked 9/11/2008 9:51:48 AM
Updated 6 days ago|4/11/2025 9:47:34 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
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Added 6 days ago|4/11/2025 9:46:34 AM
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Deleted by cruz30 [4/11/2025 9:46:54 AM]
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Calculate moles:
Moles of nitrogen: 0.44 g / 14.0 g/mol = 0.03143 mol
Moles of oxygen: 1.12 g / 16.0 g/mol = 0.07 mol
Find the ratio:
Ratio of N to O = 0.03143 / 0.07 = 1:2
Empirical formula:
Empirical formula is NO2.
Molar mass of empirical formula:
Molar mass of NO = 46.0 g/mol.
Determine molecular formula:
92.0 g/mol / 46.0 g/mol = 2, so the molecular formula is N2O4.
Added 6 days ago|4/11/2025 9:47:34 AM
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