Evaluate the discriminant for the equation. Determine the number of real solutions.
5x2+10x= 5
What is the discriminant of the quadratic equation?

5x^2+10x= 5 5x^2+10x-5=0 a=5, b=10, c=-5 discriminant=b^2-4ac=10^2-4(5)(-5)=100+100=200

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Asked 11/18/2014 9:25:14 PM

Updated 11/18/2014 9:46:24 PM

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5x^2+10x= 5

5x^2+10x-5=0

a=5, b=10, c=-5

discriminant=b^2-4ac=10^2-4(5)(-5)=100+100=200

5x^2+10x-5=0

a=5, b=10, c=-5

discriminant=b^2-4ac=10^2-4(5)(-5)=100+100=200

Added 11/18/2014 9:46:24 PM

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