Given f (x) = 17 minus x squared, what is the average rate of change in f(x) over the interval [1, 5]?
(f(5) - f(1))/(5 - 1) = (17 - 5^2 - (17 - 1^2))/4 = (17 - 25 - 17 + 1)/4 = -6.
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Asked 10/25/2020 11:22:56 PM
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