Use the Binomial Theorem to expand the binomial. (x + 2y^2)3 A. x3 - 3x^2y2 + 3xy^4 - y^6 B. x3 + 6^x2y2 + 12xy^4 + 8y^6 C. x3 - 6x^2y2 + 12xy^4

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Use the Binomial Theorem to expand the binomial. (x + 2y^2)3 A. x3 - 3x^2y2 + 3xy^4 - y^6 B. x3 + 6^x2y2 + 12xy^4 + 8y^6 C. x3 - 6x^2y2 + 12xy^4 - 8y^6 w D. x3 + 3x^2y^2 + 3xy^4 + y6

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Asked 9/29/2012 11:30:24 AM

Updated 6/10/2014 11:44:25 PM

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User: Use the Binomial Theorem to expand the binomial. (x + 2y^2)3 A. x3 - 3x^2y2 + 3xy^4 - y^6 B. x3 + 6^x2y2 + 12xy^4 + 8y^6 C. x3 - 6x^2y2 + 12xy^4 - 8y^6 w D. x3 + 3x^2y^2 + 3xy^4 + y6

Weegy: C. x3 - 6x^2y2 + 12xy^4 - 8y^6
Expert answered|jeifunk|Points 6973|

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Asked 9/29/2012 11:30:24 AM

Updated 6/10/2014 11:44:25 PM

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Flagged by yeswey [6/10/2014 11:44:25 PM]

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yeswey

(x + 2y^2)^3
= x^3 + 3x^2(2y^2) + 3x(2y^2)^2 + (2y^2)^3
= x^3 + 6x^2y^2 + 12xy^4 + 8y^6

Added 6/10/2014 11:44:22 PM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [6/10/2014 11:54:09 PM]

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Solve by graphing. x2 +2x - 8 = 0

Weegy: Solve x2 - 2x - 8 = 0 by graphing. The x intercepts are - Algebra › Algebra › Coordinate-systemSOLUTION: Solve x2 - 2x - 8 = 0 by graphing. The x intercepts are ? and ?. [ Algebra -> Algebra -> Coordinate-system -> SOLUTION: Solve x2 - 2x - 8 = 0 by ... ] (More)

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Updated 11/26/2022 12:24:35 AM

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Aj25

x^2 +2x - 8 = 0
(x - 2) ( x + 4) = 0
x = 2, x = - 2

Added 11/26/2022 12:24:30 AM

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What is the simplest form of the quotient? 4^ sqrt 400 / $^ sqrt 5 A. 5^4 SQRT 2 B, 2 ^4 sqrt 5 C. 2 sqrt 5 d. ^4 sqrt 5

Weegy: Can you kindly clarify your question please. (More)

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Updated 7/1/2023 6:35:40 AM

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Menskie

To simplify the quotient (4^( 400)) / ( 5), we can break it down step by step.

First, let's simplify 4^( 400). Since 400 = 20, we have 4^( 400) = 4^20.

Next, let's simplify 5. Since the square root of 5 cannot be simplified further, we keep it as is.

Now, the quotient becomes (4^20) / ( 5).

To simplify this expression, we can rewrite 4^20 as (2^2)^20 = 2^(2*20) = 2^40.

Therefore, the simplified form of the quotient is (2^40) / ( 5).

Added 7/1/2023 6:35:40 AM

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Simplify the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. 2d62+15d+18/2d^2+d-88 B. d^2+14d+16 / (d+8)(d-8) C. 2d^2+14d+16/(d+8)(d-8) D. 2d^2+15d+18/(d+8)(d-8)

Weegy: A. 2d62+15d+18/2d^2+d-88 is the answer. (More)

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Asked 10/1/2012 7:43:29 PM

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the sum. d^2+d-30/d^2+3d-40 + d^2+14d+48/d^2-2d-48 A. d^2+14d+16 / (d+8)(d-8) B. 2d^2+14d+16/(d+8)(d-8) C. 2d^2+15d+18/(d+8)(d-8)

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Updated 4/24/2014 12:41:55 AM

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yeswey

(d^2+d-30)/(d^2+3d-40) + (d^2+14d+48)/(d^2-2d-48)
= (d - 5)(d + 6)/(d + 8)(d - 5) + (d + 6)(d + 8)/(d - 8)(d + 6)
= (d + 6)/(d + 8) + (d + 8)/(d - 8)
= (d + 6)(d - 8)/(d + 8)(d - 8) + (d + 8)(d + 8)/(d - 8)(d + 8)
= (d^2 - 2d - 48)/(d + 8)(d - 8) + (d^2 + 16d + 64)/(d + 8)(d - 8)
= (2d^2 + 14d + 16)/(d + 8)(d - 8)

Added 4/24/2014 12:41:51 AM

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Confirmed by jeifunk [4/24/2014 12:43:37 AM]

What is the expression in factored form? 16x^2 - 25 A. (4x - 5)2 B. (4x + 5)(-4x - 5) C. (4x + 5)(4x - 5) D. (-4x + 5)(4x - 5)

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Updated 7/30/2014 10:03:25 AM

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jerry06

16x^2 - 25 = (4x + 5)(4x - 5)

Added 7/30/2014 10:03:25 AM