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Find an equation of the circle that has center (-5,6) and passes through (-1,2).
Question
Asked 2/25/2012 5:55:15 PM
Updated 7/15/2014 9:49:51 PM
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Flagged by yeswey [7/15/2014 9:49:07 PM]
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User: Find an equation of the circle that has center (-5,6) and passes through (-1,2).





Weegy: The equation for this circle is (x-(-5))^2 + (y-6)^2 = 16
Expert answered|johnlennons|Points 76|

Question
Asked 2/25/2012 5:55:15 PM
Updated 7/15/2014 9:49:51 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [7/15/2014 9:49:07 PM]
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The equation of the circle that has center (-5,6) and passes through (-1,2) is (x + 5)^2 + (y - 6)^2 = 32.
Added 7/15/2014 9:49:51 PM
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