(2a^3+5-4a+7a^2)-(4a^2-6a+3+3a^3)

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(2a^3+5-4a+7a^2)-(4a^2-6a+3+3a^3) = a^3+3a^2+2a +2

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Asked 2/8/2020 4:40:49 AM

Updated 10/24/2021 4:16:18 AM

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emdjay23

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Added 10/24/2021 4:15:11 AM

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Deleted by emdjay23 [10/24/2021 4:15:19 AM]

emdjay23

(2a^3+5-4a+7a^2)-(4a^2-6a+3+3a^3) = a^3+3a^2+2a +2

Added 10/24/2021 4:16:18 AM

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