Translate the following words to algebra symbols, using "n" as the variable.
Seven is two less than twice a number.

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Asked 6/3/2009 7:50:37 AM

Updated 2/3/2014 10:30:58 AM

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Question|Rated bad

Asked 6/3/2009 7:50:37 AM

Updated 2/3/2014 10:30:58 AM

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Seven is two less than twice a number. 2n-2=7

Added 2/3/2014 10:30:58 AM

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1/6 · a = 1 **Weegy:** this is what you need to know [ ] target=_blank>[ ' target=_blank> ]] **User:** ok is this an expert or the computer **Weegy:** this is an expert. you just spoke with the weegy program that directed you to me **User:** ok can u help me out this is my problem 1/6 · a = 1 **Weegy:** is this your school homework? **User:** im homeschoold and my mother is asleep she told me that if a have a prob to come on here for help on it **Weegy:** well waht do you need help with **User:** getting the answere to 1/6 · a = 1 **Weegy:** **User:** .ok can i ask u somthing else (More)

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Updated 9/1/2014 7:22:39 AM

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1/6 · a = 1;

1/6a = 1;

a = 6 * 1;

a = 6

1/6a = 1;

a = 6 * 1;

a = 6

Added 9/1/2014 7:22:39 AM

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5/6 · k = 10

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Updated 9/1/2014 7:21:10 AM

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5/6 · k = 10;

5/6k = 10;

k = (10)/(5/6);

k = 60/5;

k = 12

5/6k = 10;

k = (10)/(5/6);

k = 60/5;

k = 12

Added 9/1/2014 7:21:09 AM

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5/6 · k = 10
**Weegy:** (6/5)*(5/6)k=10*(6/5), 1*k=60/5, k=12 **User:** 7/10 · a = 21 **Weegy:** (10/7)*(7/10)a=21*(10/7), 1*a=210/7, a=30 (More)

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Updated 9/1/2014 7:21:52 AM

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2x = 6 wat does x = **Weegy:** -3 (More)

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Updated 8/29/2020 2:14:29 PM

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2x = 6 x= **Weegy:** 2x=6x is not something i can work with. is there more to the equation? Otherwise it is undefined. **User:** this is all it gives me Solve and check the equation, but only type in your answer as variable = solution.
2x = 6
x =
(More)

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Expert Answered

Updated 8/29/2020 2:13:00 PM

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2x = 6; x = 3

Explanation:

2x = 6

To find x divide both sides of the equation by the coefficient of x (2)

2x/2 = 6/2

x = 3

Explanation:

2x = 6

To find x divide both sides of the equation by the coefficient of x (2)

2x/2 = 6/2

x = 3

Added 8/29/2020 2:13:00 PM

This answer has been confirmed as correct and helpful.

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