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What is the discriminant in the quadratic equation x2 + 11x + 121 = x + 96? A. 20 B. 200 C. 100 D. 0
x^2 + 11x + 121 = x + 96 x^2 + 10x + 25 = 0 a = 1, b = 10, c = 25 discriminant= b^2 - 4ac = 10^2 - 4(1)(25) = 100 -100 = 0
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Asked 7/20/2018 9:16:03 AM
Updated 1/30/2021 8:51:16 AM
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x^2 + 11x + 121 = x + 96
x^2 + 10x + 25 = 0
a = 1, b = 10, c = 25
discriminant= b^2 - 4ac = 10^2 - 4(1)(25) = 100 -100 = 0

Added 1/30/2021 8:51:16 AM
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144x2
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1 Answer/Comment
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