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Factor the following polynomial completely. -x2y2 + x4 + 4y2 - 4x2 A)(x - 2)(x - 2)(x + y)(x - y) b)(x + 2)(x + 2)(x + y)(x - y) c)(x + 2)(x - 2)(x + y)(x - y)
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Asked 1/26/2011 2:56:43 PM
Updated 6/11/2014 12:41:41 AM
1 Answer/Comment
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User: Factor the following polynomial completely. -x2y2 + x4 + 4y2 - 4x2 A)(x - 2)(x - 2)(x + y)(x - y) b)(x + 2)(x + 2)(x + y)(x - y) c)(x + 2)(x - 2)(x + y)(x - y)

Weegy: (x^2-4) (x-y) (x+y)
ambrosio_09|Points 915|

User: Factor the following polynomial completely. -x2y2 + x4 + 4y2 - 4x2 A)(x - 2)(x - 2)(x + y)(x - y) b)(x + 2)(x + 2)(x + y)(x - y) c)(x + 2)(x - 2)(x + y)(x - y)

Weegy: (-4 + x^2) (x^2 - y^2)
ambrosio_09|Points 915|

User: Factor 200t + 8t3 - 80t2.

Question
Asked 1/26/2011 2:56:43 PM
Updated 6/11/2014 12:41:41 AM
1 Answer/Comment
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200t + 8t^3 - 80t^2
= 8t^3 - 80t^2 + 200t
= 8t(t^2 - 10t + 25)
= 8t(t - 5)^2
Added 6/11/2014 12:41:41 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [6/11/2014 12:53:19 AM]
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Questions asked by the same visitor
Factor 16x2 + 16x + 4 completely.
Question
Updated 8/9/2014 9:22:43 AM
1 Answer/Comment
16x^2 + 16x + 4 = 4(1 + 4x + 4x^2) = 4(2x + 1)^2

Added 8/9/2014 9:22:43 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [8/9/2014 9:28:03 AM]
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