how to tolve the long division for (x^5-5x-3x^3+4x^2+2x^4+2)÷(1-X)
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Updated 8/11/2023 2:18:34 PM
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User: how to tolve the long division for (x^5-5x-3x^3+4x^2+2x^4+2)÷(1-X)

Weegy:

Question
Updated 8/11/2023 2:18:34 PM
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1. Divide the first term of the dividend (x^5) by the divisor (1) to get x^5.
2. Multiply the divisor (1) by x^5 to get x^5.
3. Subtract x^5 from the dividend (x^5 - 5x^5) to get -5x^5.
4. Bring down the next term, which is -3x^3, to the remainder.
5. Divide -5x^5 by the divisor (1) to get -5x^5.
6. Multiply the divisor (1) by -5x^5 to get -5x^5.
7. Subtract -5x^5 from the remainder (-5x^5 - (-5x^5)) to get 0.
8. Since the remainder is now 0, you've finished the division.

The result of the division is x^5 - 5x^5 - 3x^3 + 4x^2 + 2x^4 + 2, with no remainder.

So, (x^5 - 5x - 3x^3 + 4x^2 + 2x^4 + 2) ÷ (1 - x) = x^5 - 5x^5 - 3x^3 + 4x^2 + 2x^4 + 2.

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