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Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
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Question|Rated bad
Asked 1/27/2011 8:58:39 AM
Updated 7/27/2014 1:01:12 PM
1 Answer/Comment
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Flagged by
jerry06
[7/27/2014 1:01:12 PM]
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Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
Original conversation
User:
Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
Weegy:
Whole Numbers are simply the numbers 0, 2, 4, 6. Integers are like whole numbers, but they also include negative numbers -8, -6, -4, -2, 0, 2, 4, 6 [ ]
Expert answered|scorpioblueeyes29|Points 5|
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Question|Rated bad
Asked 1/27/2011 8:58:39 AM
Updated 7/27/2014 1:01:12 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by
jerry06
[7/27/2014 1:01:12 PM]
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8
jerry06
The midpoint of the line segment whose endpoints are (-2, 5) and (6, -9) is (2, -2). M = [(-2+6/2), (5-9/2)]; M = (4/2, -4/2); M = (2, -2)
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Added 7/27/2014 1:01:11 PM
This answer has been confirmed as correct and helpful.
Confirmed by
andrewpallarca
[7/27/2014 1:03:28 PM]
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What is mode?
Weegy:
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Factor 16x2 + 16x + 4 completely.
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alfred123
16x^2 + 16x + 4 = 4(1 + 4x + 4x^2) = 4(2x + 1)^2
Added 8/9/2014 9:22:43 AM
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Confirmed by
yumdrea
[8/9/2014 9:28:03 AM]
A circle has a diameter with endpoints of (-3, 8) and (7, 4). What is the center of the circle?
Weegy:
(2, 6).
User:
Find the length of the hypotenuse of a right triangle whose legs are 5 and abs(2).
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Question
Expert Answered
Updated 8/2/2023 12:46:47 AM
1 Answer/Comment
0
Gknow
To find the length of the hypotenuse in a right triangle, you can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the two legs.
Given that the lengths of the legs are 5 and abs(2) (which is also 2), we can substitute these values into the Pythagorean theorem:
Hypotenuse^2 = Leg1^2 + Leg2^2
Hypotenuse^2 = 5^2 + 2^2
Hypotenuse^2 = 25 + 4
Hypotenuse^2 = 29
To find the length of the hypotenuse, we need to take the square root of both sides:
Hypotenuse = sqrt(29)
Using a calculator, we find that the square root of 29 is approximately 5.385.
Therefore, the length of the hypotenuse in the right triangle with legs 5 and abs(2) is approximately 5.385 units.
Added 7/6/2023 12:03:44 AM
3
Aj25
To find the center of the circle, we can use the midpoint formula, which states that the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) is ((x1 + x2) / 2, (y1 + y2) / 2).
Let's apply the formula to the given endpoints (-3, 8) and (7, 4):
Center = ((-3 + 7) / 2, (8 + 4) / 2)
Center = (4 / 2, 12 / 2)
Center = (2, 6)
So, the center of the circle is at the point (2, 6).
Added 8/2/2023 12:46:47 AM
This answer has been confirmed as correct and helpful.
true or false is this a quadratic equation. y(y + 4) - y^2 = 6
Weegy:
-11y + 3 (y - 10) = -11y + 3y - 30 = -9y - 30 craig1990|Points 205|
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y(y + 4) - y^2 = 6 is a quadratic equation. TRUE
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What is range?
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The range of a set of numbers is the highest number minus the lowest number.
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