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Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
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Asked 1/27/2011 8:58:39 AM
Updated 7/27/2014 1:01:12 PM
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User: Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).

Weegy: Whole Numbers are simply the numbers 0, 2, 4, 6. Integers are like whole numbers, but they also include negative numbers -8, -6, -4, -2, 0, 2, 4, 6 [ ]
Expert answered|scorpioblueeyes29|Points 5|

Question|Rated bad
Asked 1/27/2011 8:58:39 AM
Updated 7/27/2014 1:01:12 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by jerry06 [7/27/2014 1:01:12 PM]
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The midpoint of the line segment whose endpoints are (-2, 5) and (6, -9) is (2, -2). M = [(-2+6/2), (5-9/2)]; M = (4/2, -4/2); M = (2, -2)
Added 7/27/2014 1:01:11 PM
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Confirmed by andrewpallarca [7/27/2014 1:03:28 PM]
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Factor 16x2 + 16x + 4 completely.
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16x^2 + 16x + 4 = 4(1 + 4x + 4x^2) = 4(2x + 1)^2

Added 8/9/2014 9:22:43 AM
This answer has been confirmed as correct and helpful.
Confirmed by yumdrea [8/9/2014 9:28:03 AM]
A circle has a diameter with endpoints of (-3, 8) and (7, 4). What is the center of the circle?
Weegy: (2, 6). User: Find the length of the hypotenuse of a right triangle whose legs are 5 and abs(2). (More)
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Expert Answered
Updated 211 days ago|8/2/2023 12:46:47 AM
1 Answer/Comment
To find the length of the hypotenuse in a right triangle, you can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the two legs.

Given that the lengths of the legs are 5 and abs(2) (which is also 2), we can substitute these values into the Pythagorean theorem:

Hypotenuse^2 = Leg1^2 + Leg2^2

Hypotenuse^2 = 5^2 + 2^2
Hypotenuse^2 = 25 + 4
Hypotenuse^2 = 29

To find the length of the hypotenuse, we need to take the square root of both sides:

Hypotenuse = sqrt(29)

Using a calculator, we find that the square root of 29 is approximately 5.385.

Therefore, the length of the hypotenuse in the right triangle with legs 5 and abs(2) is approximately 5.385 units.
Added 238 days ago|7/6/2023 12:03:44 AM
To find the center of the circle, we can use the midpoint formula, which states that the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) is ((x1 + x2) / 2, (y1 + y2) / 2).

Let's apply the formula to the given endpoints (-3, 8) and (7, 4):

Center = ((-3 + 7) / 2, (8 + 4) / 2)
Center = (4 / 2, 12 / 2)
Center = (2, 6)

So, the center of the circle is at the point (2, 6).
Added 211 days ago|8/2/2023 12:46:47 AM
This answer has been confirmed as correct and helpful.
true or false is this a quadratic equation. y(y + 4) - y^2 = 6
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Updated 217 days ago|7/26/2023 9:50:33 AM
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y(y + 4) - y^2 = 6 is a quadratic equation. TRUE
Added 217 days ago|7/26/2023 9:50:33 AM
This answer has been confirmed as correct and helpful.
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