mass in grams of 1.35 mol Fe

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75.4 g Fe

Expert answered|theresearcher|Points 1080|

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Asked 8/29/2010 3:19:30 AM

Updated 7/20/2023 4:33:57 AM

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Bench_14

Solution:
Now, you can calculate the mass of 1.35 moles of iron (Fe):

Mass (grams) = Number of moles × Molar mass
Mass (grams) = 1.35 mol × 55.845 g/mol
Mass (grams) 75.35675 grams

So, the mass of 1.35 moles of iron (Fe) is approximately 75.36 grams.

Added 7/20/2023 4:33:57 AM

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% comp of SO4 in Na2SO4

Weegy: % comp of SO4 in Na2SO4 = 67.6% (More)

Question

Expert Answered

Updated 9/28/2023 2:42:37 PM

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Bench_14

Solution:
1. Calculate the molar mass of SO4:
- Sulfur (S) has a molar mass of approximately 32.07 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.
- Since there are four oxygen atoms in SO4, multiply the molar mass of oxygen by 4: 16.00 g/mol * 4 = 64.00 g/mol.
- Now, add the molar mass of sulfur and the molar mass of oxygen: 32.07 g/mol + 64.00 g/mol = 96.07 g/mol.

2. Calculate the molar mass of Na2SO4:
- Sodium (Na) has a molar mass of approximately 22.99 g/mol.
- Since there are two sodium atoms in Na2SO4, multiply the molar mass of sodium by 2: 22.99 g/mol * 2 = 45.98 g/mol.
- Add this to the molar mass of SO4 calculated earlier: 45.98 g/mol + 96.07 g/mol = 142.05 g/mol.

3. Calculate the percent composition of SO4 in Na2SO4:
- Divide the molar mass of SO4 (96.07 g/mol) by the molar mass of Na2SO4 (142.05 g/mol) and multiply by 100 to get the percentage: (96.07 g/mol / 142.05 g/mol) * 100 67.64%.

So, the percent composition of SO4 in Na2SO4 is approximately 67.64%.

Added 9/28/2023 2:42:37 PM

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Calculate the # of sodium ions in 0.949 mol of sodium chloride. How many Na+ ions are there in 0.949 mol of NaCl?

Weegy: 22 (More)

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Updated 10/22/2023 9:30:28 AM

1 Answer/Comment

MR.READ

Number of sodium ions = Number of chloride ions = 0.949 moles x 6.022 x 10²³ ions/mole
Number of sodium ions = 0.949 moles x 6.022 x 10²³ ions/mole 5.70 x 10²³ sodium ions
There are approximately 5.70 x 10²³ sodium ions in 0.949 moles of sodium chloride (NaCl).

Added 10/22/2023 9:30:28 AM

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Calculate the # of sodium ions in 0.949 mol of sodium chloride. How many Na+ ions are there in 0.949 mol of NaCl?

Weegy: 77.76 (More)

Question

Expert Answered

Updated 51 days ago|10/21/2025 11:11:19 AM

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cruz30

1 mol of any substance = 6.022 × 10^23 particles
Use the formula
Number of Na+ ions = moles of NaCl × 6.022 × 10^23
Given:
Moles of NaCl = 0.949
Calculate
Number of Na+ ions = 0.949 × 6.022 × 10^23
Number of Na+ ions = 5.715 × 10^23
Answer:
5.72 × 10^23 Na+ ions

Added 51 days ago|10/21/2025 11:11:17 AM

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User: In 4 NH3 (g) + 5 O2 (g) ---> 4 NO (g) + 6 H2O (l) the total number of moles of products formed when 1.20 mole of ammonia reacts is

Weegy: 25 (More)

Question

Expert Answered

Updated 85 days ago|9/17/2025 12:35:51 PM

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cruz30

Write the balanced equation
4 NH3(g) + 5 O2(g) : 4 NO(g) + 6 H2O(l)
Determine the mole ratio
From the equation: 4 moles NH3 produce 4 moles NO + 6 moles H2O
Total moles of products per 4 moles NH3 = 4 + 6 = 10 moles
Calculate total moles for 1.20 moles of NH3
Total moles of products = (10 / 4) × 1.20
Total moles of products = 3.0
Answer: 3.0 moles of products are formed

Added 85 days ago|9/17/2025 12:35:45 PM

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mass of 1.00 mol sodium

Weegy: Sodium has an atomic mass of 22.99. Therefore 1 mole of it weighs 22.99 grams. Similarly a mole of bromine weighs 79.9 grams. [ A mole of sodium bromide - NaBr - contains 1 mole each of sodium and bromine (note that this is not true for all chemical salts) and so 1 mole of it weighs 102.89 grams. ] (More)

Question

Expert Answered

Updated 7/20/2023 4:37:05 AM

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Bench_14

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Added 7/20/2023 4:35:39 AM

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Deleted by Bench_14 [7/20/2023 4:35:48 AM], Unflagged by Bench_14 [1/1/2024 8:34:02 AM], Flagged by Bench_14 [1/1/2024 8:34:30 AM], Deleted by Bench_14 [1/1/2024 8:34:31 AM]

Bench_14

Solution:
The molar mass of sodium (Na) is approximately 22.99 grams per mole (g/mol).

Therefore, the mass of 1.00 mole of sodium is:

1.00 mol x 22.99 g/mol 22.99 grams

So, the mass of 1.00 mole of sodium is approximately 22.99 grams.

Added 7/20/2023 4:37:05 AM

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