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i need help with this physics question.
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Asked 6/5/2012 4:56:54 PM
Updated 6/14/2024 9:13:52 AM
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User: i need help with this physics question.

Weegy: Two pistons push down on the fluid filling two cylinders connected by a narrow hose. The area A1 is 1 square inch, and the area A2 is 10 square inches. A force of 4 pounds is exerted downward on pistom A1. The pressure on A1 in psi is?
Autumn2014|Points 291|

User: How many significant digits are in the measurement 0.00210 mg?

User: Express 7.3 mg in g. (Do not use scientific notation for this answer.)

User: How many significant digits are in the measurement 589.040 Newtons?

User: Multiply these measurements, using significant digit rules: 1.27 kg x 9.8 m/s2 =

Weegy: 1.27 kg * 9.8 m/s2= 12.4.
Expert answered|eturker|Points 2049|



Question
Asked 6/5/2012 4:56:54 PM
Updated 6/14/2024 9:13:52 AM
3 Answers/Comments
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The measurement 0.00210 mg has three significant digits. The significant digits are 2, 1, and the final 0.

Added 6/14/2024 9:08:08 AM
This answer has been confirmed as correct and helpful.
3
Solution:
7.3 { mg} = {7.3 { mg}}/{1,000}
7.3 { mg} = 0.0073 { g}

So, 7.3 mg is equal to 0.0073 grams.
Added 6/14/2024 9:09:35 AM
This answer has been confirmed as correct and helpful.
3
Solution:
1.27 kg has three significant digits.
9.8 m/s² has two significant digits.

1.27 {kg} × 9.8 {m/s}^2 = 12.446 {kg}×{m/s}^2
12.446 {kg}×{m/s}^2 = 12 {kg}×{m/s}^2

So, the result of ( 1.27 {kg} × 9.8 {m/s}^2 ) is ( 12 {kg ×{m/s}^2 ).
Added 6/14/2024 9:13:52 AM
This answer has been confirmed as correct and helpful.
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