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Factor completely. -2k - k3 - 3k2
-2k - k3 - 3k^2 The factors are: -k (k+2) (k+1)
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Asked 7/12/2011 1:14:45 PM
Updated 1/31/2014 3:17:19 PM
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-2k - k3 - 3k^2

The factors are: -k (k+2) (k+1)

Added 1/31/2014 3:17:19 PM
This answer has been confirmed as correct and helpful.
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Factor completely. x^2-10x+24
Weegy: x^2 - 10x + 24 = (x - 4)(x - 6) (More)
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Expert Answered
Updated 3/30/2015 6:07:58 AM
0 Answers/Comments
Factor completely. 49t^6 - 4k^8
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Not Answered
Updated 6/16/2014 11:11:27 AM
1 Answer/Comment
49t^6 - 4k^8 = -(2 k^4-7 t^3) (2 k^4+7 t^3)
Added 6/16/2014 11:11:27 AM
This answer has been confirmed as correct and helpful.
What is the solution set of 7x^2 + 3x = 0?
Weegy: First you will want to take the 5 and multiply it to the -3X and 4 so it will look like this: 7X -15X-20=-21-7X Got it? Then you will combine the X's on the first side so you will get this: -8X-20= -21-7X Next you need to get the X's on [ [ [ one side so you will take the one that is less, in this case -8X and add it to the -7X. When it crosses over the equal mark it becomes a positive so you will get this next: -20=-21 + X <------you get 1X here but it is not necessary to put the 1 Next you want to get the X by itself so you will add the-21 (because it is the lowest) to the other side. Again, when you cross a negative to the other side it becomes a positive. So here is your final result: 1=X Hope that helped! ] ] ] (More)
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Expert Answered
Updated 8/17/2014 3:03:21 PM
1 Answer/Comment
7x^2 + 3x = 0;

x(7x + 3) = 0;

x = 0;

7x + 3 = 0;
7x = -3;
x = -3/7;

x = {0, -3/7}
Added 8/17/2014 3:03:21 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/17/2014 3:08:45 PM]
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