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Select the term that describes the constant portion in this quadratic equation. 7x2 - 12x + 16 = 0
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Asked 1/22/2014 10:57:18 AM
Updated 1/22/2014 11:59:56 PM
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Flagged by yeswey [1/22/2014 11:59:37 PM]
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User: Select the term that describes the constant portion in this quadratic equation. 7x2 - 12x + 16 = 0

Weegy: (x-3)^2 (2 x+1) = 0 , 343/54 - (49 (-11/6 + x))/6 + 2 (-11/6 + x)^3 == 0 [ ]
cjabward|Points 760|

User: Select the term that describes the constant portion in this quadratic equation. 7x2 - 12x + 16 = 0 -12x 7x2 16

Weegy: (x-3)^2 (2 x+1) = 0 , 343/54 - (49 (-11/6 + x))/6 + 2 (-11/6 + x)^3 == 0 [ ]
cjabward|Points 760|

Question
Asked 1/22/2014 10:57:18 AM
Updated 1/22/2014 11:59:56 PM
1 Answer/Comment
This conversation has been flagged as incorrect.
Flagged by yeswey [1/22/2014 11:59:37 PM]
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the term that describes the constant portion in this quadratic equation 7x2 - 12x + 16 = 0 is 16
Added 1/22/2014 11:59:56 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/28/2014 12:29:42 AM], Rated good by andrewpallarca
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Questions asked by the same visitor
Select the term that describes the quadratic portion in this quadratic equation. 7x2 - 12x + 16 = 0 -12x 7x2 16
Weegy: (x-3)^2 (2 x+1) = 0 , 343/54 - (49 (-11/6 + x))/6 + 2 (-11/6 + x)^3 == 0 [ ] (More)
Question
Updated 1/22/2014 11:54:34 PM
1 Answer/Comment
the term that describes the quadratic portion in this quadratic equation 7x2 - 12x + 16 = 0 is 7x2

Added 1/22/2014 11:54:32 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [6/28/2014 12:29:45 AM], Rated good by andrewpallarca
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