The distance between the points (5, -2) and (-7, 3) is
Question
Updated 7/3/2014 8:33:43 PM
Flagged by yeswey [7/3/2014 8:31:54 PM]
s
Original conversation
User: The distance between the points (5, -2) and (-7, 3) is

User: The distance between the points (5, -2) and (-7, 3) is v5 v29 13

Question
Updated 7/3/2014 8:33:43 PM
Flagged by yeswey [7/3/2014 8:31:54 PM]
Rating
3
The distance between the points (5, -2) and (-7, 3) is sqrt [(-7-5)^2+(3-(-2))^2] = sqrt (144+25) = sqrt 169 = 13.
Confirmed by yumdrea [7/4/2014 10:18:50 PM]

Questions asked by the same visitor
The equation of the circle whose center is at (3, 7) and whose radius is 6 is (x + 3)² + (y + 7)² = 6 (x + 3)² + (y + 7)² = 36 (x - 3)² + (y - 7)² = 36
Weegy: the radius is 6 User: |P1P2| = d = (More)
Question
Updated 7/3/2014 8:41:51 PM
The equation of the circle whose center is at (3, 7) and whose radius is 6 is: (x - 3)² + (y - 7)² = 36
Confirmed by yumdrea [7/4/2014 2:01:51 PM]
Find the product of (5a - 7)(2a - 1)?
Question
Updated 1/28/2018 7:24:33 AM
(5a - 7)(2a - 1)
= 10a^2 - 5a - 14a + 7
= 10^2 - 19a + 7
Write the equation of the given circle. center (-2, -2) radius of 6
Weegy: (x + 2)2 + (y - 4)2 = 49 User: The foci are located at (6, 0) and (-6, 0) (0, 6) and (0, -6) (0, 8) and (0, -8) (More)
Question
Updated 7/3/2014 8:41:11 PM
The equaton of the circle with center (-2, -2) radius of 6 is (x + 2)^2 + (y + 2)^2 = 36.
Confirmed by yumdrea [7/4/2014 2:02:02 PM]
Write the equation of the given circle. center (3, 3) radius of 2
Question
Updated 7/3/2014 8:40:00 PM
The equation of the circle with center (3, 3) and radius 2 is (x - 3)^2 + (y - 3)^2 = 4.
Confirmed by yumdrea [7/4/2014 2:02:41 PM]
4y2 + 25y + 6
Weegy: 4y2 + 25y + 6 = (y + 6) (4y + 1) User: Factor 6a^2 - 23a - 4. (More)
Question
Updated 8/3/2014 9:54:34 PM
6a^2 - 23a - 4 = (a - 4) (6a + 1)
Confirmed by jeifunk [8/3/2014 9:54:12 PM]
32,020,350
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