Question and answer
The equation of the circle whose center is (0, 0) and radius is length 9 is x² + y² = 3 x² + y² = 9 x² + y² = 81
Question
Asked 2/2/2015 11:08:40 AM
Updated 2/2/2015 10:09:23 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [2/2/2015 10:08:31 PM]
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Original conversation
User: Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (0, - 3) interior exterior on the circle

User: The equation of the circle whose center is (0, 0) and radius is length 9 is x² + y² = 3 x² + y² = 9 x² + y² = 81

Weegy: The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)? + (y - 1)? = 9.



User: Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (5, -3) interior exterior on the circle

Weegy: 1.4 - (-3.6)

= 1.4 + 3.6;

= 5


User: Find the coordinates of the center of the following circle. (x - 5)² + (y + 3)² = 25 (5, 3) (-5, 3) (5, -3)

Weegy: -3x(-3)-(-5) = 9x + 5
Andrew.|Points 48379|

User: Enter the equation of the circle described below. Center (5, 2), radius = 3

User: Enter the equation of the circle described below. Center (3, -2), radius = 5

User: Enter the equation of the circle described below. Center (-3, 0), radius

Weegy: The equation of a circle with a center at (-3,0) and a radius of square root of 5 is (x + 3)^2 + y^2 = 5.



User: Enter the equation of the circle described below. Center (0, 0), radius = 4

Question
Asked 2/2/2015 11:08:40 AM
Updated 2/2/2015 10:09:23 PM
5 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [2/2/2015 10:08:31 PM]
New answers
Rating
3
The point (0, - 3) is on the circle (x - 5)^2 + (y + 3)^2 = 25.
(0 - 5)^2 + (-3 + 3)^2 = (-5)^2 + 0^2 = 25, so its on the circle.
Added 2/2/2015 10:05:24 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [2/3/2015 1:38:50 AM]
3
The equation of the circle whose center is (0, 0) and radius is length 9 is x² + y² = 81.
Added 2/2/2015 10:05:57 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [2/3/2015 1:39:04 AM]
3
The point (5, -3) is interior the circle (x - 5)^2 + (y + 3)^2 = 25.
Added 2/2/2015 10:07:25 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [2/3/2015 1:39:18 AM]
3
The coordinates of the center of the circle (x - 5)² + (y + 3)² = 25 is (5, -3).
Added 2/2/2015 10:08:14 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [2/3/2015 1:39:27 AM]
3
Tthe equation of the circle with Center (0, 0), radius = 4 is x^2 + y^2 = 16
Added 2/2/2015 10:09:23 PM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [2/3/2015 1:39:35 AM]
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Questions asked by the same visitor
Indicate in standard form the equation of the line passing through the given points. L(5, 0), M(0, 5)
Question
Not Answered
Updated 2/10/2015 4:47:06 AM
1 Answer/Comment
The standard form the equation of the line passing through the given points. L(5, 0), M(0, 5) is x + y = 5 .
slope = (5 - 0)/(0 - 5) = -1
y = -x + 5
x + y = 5
Added 2/10/2015 4:47:06 AM
This answer has been confirmed as correct and helpful.
Confirmed by Andrew. [2/10/2015 4:51:55 AM]
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