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Solve for y. a=(x+y+z)/3
Question
Asked 4/23/2013 1:21:14 PM
Updated 5/27/2014 8:48:47 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [5/27/2014 8:47:22 PM]
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User: Solve for y. a=(x+y+z)/3 y = a - 3x - z y = a - x - 3z y = 3a - x - z

User: Solve for y. a=(x+y+z)/3

Weegy: Simplifying (x * y) + (x * z) + (y * z) = t Multiply x * y (xy) + (x * z) + (y * z) = t xy + (x * z) + (y * z) = t Multiply x * z xy + (xz) + (y * z) = t xy + xz + (y * z) = t Multiply y * z xy + xz + (yz) = t xy + xz + yz = [ t Solving xy + xz + yz = t Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1yz' to each side of the equation. xy + xz + yz + -1yz = t + -1yz Combine like terms: yz + -1yz = 0 xy + xz + 0 = t + -1yz xy + xz = t + -1yz Reorder the terms: -1t + xy + xz + yz = t + -1yz + -1t + yz Reorder the terms: -1t + xy + xz + yz = t + -1t + -1yz + yz Combine like terms: t + -1t = 0 -1t + xy + xz + yz = 0 + -1yz + yz -1t + xy + xz + yz = -1yz + yz Combine like terms: -1yz + yz = 0 -1t + xy + xz + yz = 0 ]
Lorindaleigh|Points 93|

User: Solve for k. 9/(2k-3)=4/(k+1) -3 21 -21

Weegy: You did not provide us with any equations containing k!
eturker|Points 2883|

Question
Asked 4/23/2013 1:21:14 PM
Updated 5/27/2014 8:48:47 PM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [5/27/2014 8:47:22 PM]
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3
a=(x+y+z)/3
3a = x + y + z
y = 3a - x - z
Added 5/27/2014 8:47:41 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/28/2014 11:17:56 AM]
3
9/(2k-3)=4/(k+1)
9(k+1)=4(2k-3)
9k+9 = 8k-12
9k-8k =-12-9
k=-21
Added 5/27/2014 8:48:47 PM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/28/2014 11:17:58 AM]
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