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Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. What must she score on her 4th test so she will have at least an 85 average?
Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. To have at least an 85 average, she must score at least 91 on her 4th test. (75+83+91+x)/4=85 249+x=85*4 249+x=340 x=340-249 x=91
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Asked 11/13/2010 2:37:34 AM
Updated 1/9/2016 6:54:40 AM
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Jocelyn has test scores of 75, 83 and 91 on her first three algebra tests. To have at least an 85 average, she must score at least 91 on her 4th test.
(75+83+91+x)/4=85
249+x=85*4
249+x=340
x=340-249
x=91
Added 1/9/2016 6:54:40 AM
This answer has been confirmed as correct and helpful.
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