In a group of 10 students, probability that two specific students are not seated together in a row

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Total arrangements = 10! = 3,628,800 Arrangements with 2 together treat as 1: 9! × 2 = 725,760 Not together = 10! - 9!×2 = 3,628,800 - 725,760 = 2,903,040 Probability = 2,903,040 / 3,628,800 = 8/10 = 0.8

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Asked 12 days ago|2/23/2026 9:23:02 AM

Updated 12 days ago|2/23/2026 10:01:54 AM

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cruz30

Total arrangements = 10! = 3,628,800
Arrangements with 2 together treat as 1: 9! × 2 = 725,760
Not together = 10! - 9!×2 = 3,628,800 - 725,760 = 2,903,040
Probability = 2,903,040 / 3,628,800 = 8/10 = 0.8

Added 12 days ago|2/23/2026 10:01:33 AM

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Salas1987

(9! * 2!) / 10! = (9! * 2) / (10 * 9!) = 2/10 = 1/5.
Therefore, the probability that the two specific students are not seated together is 1 - (1/5) = 4/5.

Added 12 days ago|2/23/2026 10:01:54 AM

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