Using the discriminant, determine the nature of the roots of the following equations (DO NOT SOLVE): 2p2 – p – 4 = 0
2p^2 – p – 4 = 0 a = 2, b = -1, c = -4 discriminant = b^2 - 4ac = (-1)^2 - 4(2)(-4) = 1 + 32 = 33 > 0 there are two real and irrational roots for the equation 2p^2 – p – 4 = 0.
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Updated 1/13/2015 11:31:47 PM
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2p^2 – p – 4 = 0
a = 2, b = -1, c = -4
discriminant = b^2 - 4ac = (-1)^2 - 4(2)(-4) = 1 + 32 = 33 > 0
there are two real and irrational roots for the equation 2p^2 – p – 4 = 0.
Confirmed by jeifunk [1/13/2015 11:38:58 PM]

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