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32 g oxygen gas occupies 25 L at 300 K. Determine pressure using R = 0.0821.
Given: Mass m = 32 g Molar mass M = 32 g/mol n = 32/32 = 1 mol V = 25 L T = 300 K R = 0.0821 L·atm/mol·K Ideal gas law: PV = nRT P = nRT / V P = (1 × 0.0821 × 300) / 25 P = 24.63 / 25 P = 0.985 atm Answer: 0.985 atm
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Asked 13 days ago|2/1/2026 10:35:35 AM
Updated 12 days ago|2/2/2026 5:55:37 AM
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Given:
Mass m = 32 g
Molar mass M = 32 g/mol n = 32/32 = 1 mol
V = 25 L
T = 300 K
R = 0.0821 L·atm/mol·K
Ideal gas law: PV = nRT
P = nRT / V
P = (1 × 0.0821 × 300) / 25
P = 24.63 / 25
P = 0.985 atm
Answer: 0.985 atm
Added 12 days ago|2/2/2026 5:54:38 AM
This answer has been confirmed as correct and helpful.
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[Deleted]
Added 12 days ago|2/2/2026 5:54:47 AM
Deleted by Salas1987 [2/2/2026 5:54:49 AM]
0
PV = nRT.
n = 32 g / 32 g/mol = 1 mol. Given V = 25 L, T = 300 K, and R = 0.0821L.

atm/(mol.K).
Rearranging the ideal gas law to solve for P: P = nRT/V.

Plugging in the values: P = (1 mol * 0.0821 L.atm/(mol.K) * 300 K) / 25 L. P = 24.63 / 25 atm. P = 0.9852 atm.
Added 12 days ago|2/2/2026 5:55:37 AM
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Updated 12 days ago|2/2/2026 6:00:11 AM
1 Answer/Comment
Given:
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1 Answer/Comment
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Added 12 days ago|2/2/2026 5:57:27 AM
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Question
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Updated 12 days ago|2/2/2026 5:49:57 AM
2 Answers/Comments
Given:
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Added 12 days ago|2/2/2026 5:48:07 AM
This answer has been confirmed as correct and helpful.
[Deleted]
Added 12 days ago|2/2/2026 5:49:57 AM
Deleted by Salas1987 [2/2/2026 5:50:04 AM]
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1 Answer/Comment
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1 Answer/Comment
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Added 12 days ago|2/2/2026 5:51:46 AM
This answer has been confirmed as correct and helpful.
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