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two charges separated by 1 meter exert a 1 N force on each other. if the magnitude of each charge is doubled , the fouce on each charge is
4N
Expert answered|tntpugh5|Points 325|Rating ***** (+65 -2)
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Asked 1/29/2009 9:42:25 AM
Updated 358 days ago|7/28/2025 11:14:10 AM
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Coulomb’s Law Formula:
F = k × (q × q ) / r²
F_new = k × (2q × 2q) / r²
F_new = k × (4q²) / r²
F_new = 4 × F
Answer:
The new force is 4 N — four times the original force.
Added 358 days ago|7/28/2025 11:14:10 AM
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