What is the center and radius of the circle shown by the equation?
(x+8)2 + (y+3)2 = 6.25
A. (–8, –3); r = 3.125
B. (–8, –3); r = 2.5
C. (8, 3); r = 2.5
D. (8, 3); r = 3.125

What is the center and radius of the circle shown by the equation?
(x+8)2 + (y+3)2 = 6.25
A. (–8, –3); r = 3.125
B. (–8, –3); r = 2.5
C. (8, 3); r = 2.5
D. (8, 3); r = 3.125

The center and radius of the circle shown by the equation (x+8)^2 + (y+3)^2 = 6.25 is: the center (–8, –3); r = 2.5

What is the center and radius of the circle shown by the equation? (x+8)2 + (y+3)2 = 6.25 A. (–8, –3); r = 3.125 B. (–8, –3); r = 2.5 C. (8, 3); r = 2.5 D. (8, 3); r = 3.125

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