solve the following system by substitution 3x-2y=-9 2x+y=1
3x-2y=-9_2x+y=1 Since 2x does not contain the variable to solve for, [ move it to the right-hand side of the equation by subtracting 2x from both sides. 3x-2y=-9_y=-2x+1... Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is -2x+1. 3x-2(-2x+1)=-9_y=-2x+1... Multiply -2 by each term inside the parentheses. 3x+4x-2=-9_y=-2x+1... Since 3x and 4x are like terms, add 4x to 3x to get 7x. 7x-2=-9_y=-2x+1... Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2
to both sides. 7x=2-9_y=-2x+1... Subtract 9 from 2 to get -7. 7x=-7_y=-2x+1... Divide each term in the equation by 7. (7x)/(7)=-(7)/(7)_y=-2x+1... Simplify the left-hand side of the equation by canceling the common factors. x=-(7)/(7)_y=-2x+1... Simplify the right-hand side of the equation by simplifying each term. x=-1_y=-2x+1... Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is -1. x=-1_y=-2(-1)+1... Multiply -2 by each term inside the parentheses. x=-1_y=2+1... Add 1 to 2 to get 3. x=-1.... x=-1 and y=3 is the answer. ]
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solve the following system by substitution 3x - 2y = -9 2x + y = 1
Weegy: User: solve the following system by substitution -6x - y = 1 3x - 4y = 31 (More)
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Updated 11/29/2017 8:35:29 AM
3x - 2y = -9
2x + y = 1
y = -2x + 1

3x - 2(-2x + 1) = -9
3x + 4x - 2 = -9
7x - 2 = -9
7x = -9 + 2
7x = -7
x = -7/7
x = -1

2(-1) + y = 1
-2 + y = 1
y = 1 + 2
y = 3

Solution set: (-1, 3)

-6x - y = 1
3x - 4y = 31
(-y = 6x + 1)/(-1)
y = -6x - 1

3x - 4(-6x - 1) = 31
3x + 24x + 4 = 31
27x + 4 = 31
27x = 31 - 4
27x = 27
x = 27/27
x = 1

-6(1) - y = 1
-6 - y = 1
-y = 1 + 6
-y = 7
y = -7

Solution set: (1, -7)
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