16y2 – 8y + 1
Question
Updated 8/19/2014 1:13:21 AM
Flagged by yeswey [8/19/2014 1:13:00 AM]
s
Original conversation
User: 16y2 – 8y + 1

Question
Updated 8/19/2014 1:13:21 AM
Flagged by yeswey [8/19/2014 1:13:00 AM]
Rating
3
16y^2 – 8y + 1 = (4y - 1)(4y - 1) = (4y - 1)^2
Confirmed by andrewpallarca [8/19/2014 1:16:51 AM]

Questions asked by the same visitor
4x^2 – 13x + 3 = 0
Question
Updated 7/19/2018 5:48:34 PM
4x^2 – 13x + 3 = 0

(x - 3)(4x - 1) = 0;

x - 3 = 0;
x = 3

4x - 1 = 0;
4x = 1;
x = 1/4;

x = 3 or x = 1/4
5x2 – 8x - 4
Weegy: For an equation of a line in the form y = mx+c, 'm' denotes the slope. Hence here, the slope is 8 and the y-intercept of the line is -7(i.e. 7 units on the negative Y-axis) (More)
Question
Updated 8/19/2014 1:14:28 AM
5x^2 – 8x - 4 = (x - 2)(5x + 2)

Confirmed by jeifunk [8/19/2014 6:22:06 AM]
(16x2 – 56x + 40) ÷ 8 User: (?12w?^4-?6w?^3+w^2)/?3w?^2
Weegy: 2x^2 - 7x + 5. (More)
Question
Updated 5/26/2014 11:22:37 PM
I think this expert gave the answer to the first question. It should be correct.
yeswey, during live conversation, we are supposed to answer the last question. Prior questions can be answered on the archives. That's the reason it was flagged - the expert did not answer the question that was asked.
Okay, thanks.
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