Question and answer
16y2 – 8y + 1
Question
Asked 6/13/2013 11:40:04 PM
Updated 8/19/2014 1:13:21 AM
1 Answer/Comment
Flagged by yeswey [8/19/2014 1:13:00 AM]
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Original conversation
User: 16y2 – 8y + 1

Question
Asked 6/13/2013 11:40:04 PM
Updated 8/19/2014 1:13:21 AM
1 Answer/Comment
Flagged by yeswey [8/19/2014 1:13:00 AM]
New answers
Rating
3
16y^2 – 8y + 1 = (4y - 1)(4y - 1) = (4y - 1)^2
Added 8/19/2014 1:13:21 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [8/19/2014 1:16:51 AM]
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Questions asked by the same visitor
4x^2 – 13x + 3 = 0
Question
Updated 7/19/2018 5:48:34 PM
1 Answer/Comment
4x^2 – 13x + 3 = 0

(x - 3)(4x - 1) = 0;

x - 3 = 0;
x = 3

4x - 1 = 0;
4x = 1;
x = 1/4;

x = 3 or x = 1/4
Added 7/19/2018 5:48:12 PM
This answer has been confirmed as correct and helpful.
5x2 – 8x - 4
Weegy: For an equation of a line in the form y = mx+c, 'm' denotes the slope. Hence here, the slope is 8 and the y-intercept of the line is -7(i.e. 7 units on the negative Y-axis) (More)
Question
Updated 8/19/2014 1:14:28 AM
1 Answer/Comment
5x^2 – 8x - 4 = (x - 2)(5x + 2)

Added 8/19/2014 1:14:28 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [8/19/2014 6:22:06 AM]
(16x2 – 56x + 40) ÷ 8 User: (?12w?^4-?6w?^3+w^2)/?3w?^2
Weegy: 2x^2 - 7x + 5. (More)
Question
Expert Answered
Updated 5/26/2014 11:22:37 PM
4 Answers/Comments
I think this expert gave the answer to the first question. It should be correct.
Added 5/26/2014 11:15:45 PM
yeswey, during live conversation, we are supposed to answer the last question. Prior questions can be answered on the archives. That's the reason it was flagged - the expert did not answer the question that was asked.
Added 5/26/2014 11:19:51 PM
Okay, thanks.
Added 5/26/2014 11:22:37 PM
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