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0.3x^2+0.4x^2-0.2x^2=
Question
Asked 5/12/2013 10:09:47 PM
Updated 5/27/2014 9:17:37 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [5/27/2014 9:14:28 AM]
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Original conversation
User: 0.3x^2+0.4x^2-0.2x^2=

Weegy: 0.5x^3
shifa saleheen|Points 9966|

User: By using the method of substitution to solve the system of linear equations for 2x-y=6 7x-3y=22. What is the solution?

Question
Asked 5/12/2013 10:09:47 PM
Updated 5/27/2014 9:17:37 AM
2 Answers/Comments
This conversation has been flagged as incorrect.
Flagged by yeswey [5/27/2014 9:14:28 AM]
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0.3x^2+0.4x^2-0.2x^2
= 0.7x^2-0.2x^2
= 0.5x^2
Added 5/27/2014 9:14:12 AM
This answer has been confirmed as correct and helpful.
Confirmed by andrewpallarca [5/27/2014 9:16:12 AM]
3
2x-y=6 rearranging the equation we can get:
y = 2x - 6 (equation 1)
7x-3y=22 (equation 2)
using equation 1 to substitute y in the equation 2 the result is:
7x - 3(2x - 6) = 22
7x - 6x + 18 = 22
x = 22 - 18 = 4
y = 2(4) - 6 = 2
The solution for the system 2x-y=6 7x-3y=22 is (4, 2)
Added 5/27/2014 9:17:37 AM
This answer has been confirmed as correct and helpful.
Confirmed by jeifunk [5/27/2014 9:20:06 AM], Unconfirmed by jeifunk [5/27/2014 9:28:53 AM], Confirmed by andrewpallarca [5/27/2014 11:47:02 AM]
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