divide and simplify (r^2) / (r^12)

(r^2) / (r^12)=r^2-12=r^-10
The answer is r^-10 or r to the -10th power.

Expert answered|cheripearson|Points 44|

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Asked 1/22/2012 7:25:47 PM

Updated 6/30/2014 8:39:49 AM

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if the sides of a square are lengthened by cm, the area becomes 121cm^2. find the length of a side of the orginal square. **Weegy:** lengthened by how many cm? (More)

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Asked 1/22/2012 5:05:28 PM

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if the sides of a square are lengthened by 6cm, the area becomes 121cm^2. find the length of a side of the orginal square. **Weegy:** If the original square side is x, x>0
=> when it's lengthened it is x+6
S=x^2
S1 = (x+6)^2 = 121,
=> x^2+12x + 36 = 121,
x^2+ 12x - 75=0,
=> x =-17 and x = 5,
but x>0
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divide and simplify ((2v-6)/9)/((v-3)/21v)

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Updated 6/30/2014 1:59:56 AM

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((2v-6)/9)/((v-3)/21v)

=(42v-126)/(-27v+9v2)

=(14v 42)/(-9v+3v2)

=(42v-126)/(-27v+9v2)

=(14v 42)/(-9v+3v2)

Added 6/30/2014 1:59:56 AM

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