A doctor's office has a jar of 22 lollipops; 12 are lime, 7 are cherry, 2 are grape, and 1 is orange. If Jennifer and Seth each take and eat a lollipop at random, what is the probability that Jennifer will choose a grape lollipop and Seth will chooe a cherry one? A) 7/282 B) 1/33 C) 21/484

B 1/33

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Expert answered|SarahGCarpio|Points 0|

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Asked 2/22/2013 7:31:50 AM

Updated 311 days ago|9/10/2023 3:05:56 PM

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In this scenario, the doctor's office has a total of 22 lollipops. Out of these 22 lollipops, 2 are grape and 7 are cherry.

So, the probability of Jennifer choosing a grape lollipop is 2/22, since there are 2 grape lollipops out of a total of 22 lollipops.

After Jennifer takes a lollipop, there will be 21 lollipops left. Out of these 21 lollipops, 7 are cherry.

Therefore, the probability of Seth choosing a cherry lollipop is 7/21, since there are 7 cherry lollipops out of a total of 21 lollipops.

To find the probability of both events happening, we multiply the probabilities of each event occurring:

(2/22) * (7/21) = 14/462

Simplifying the fraction, we get:

14/462 = 1/33

So, the probability that Jennifer will choose a grape lollipop and Seth will choose a cherry lollipop is 1/33.

So, the probability of Jennifer choosing a grape lollipop is 2/22, since there are 2 grape lollipops out of a total of 22 lollipops.

After Jennifer takes a lollipop, there will be 21 lollipops left. Out of these 21 lollipops, 7 are cherry.

Therefore, the probability of Seth choosing a cherry lollipop is 7/21, since there are 7 cherry lollipops out of a total of 21 lollipops.

To find the probability of both events happening, we multiply the probabilities of each event occurring:

(2/22) * (7/21) = 14/462

Simplifying the fraction, we get:

14/462 = 1/33

So, the probability that Jennifer will choose a grape lollipop and Seth will choose a cherry lollipop is 1/33.

Added 311 days ago|9/10/2023 3:05:56 PM

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