Parallelogram

Question

Asked 2/17/2015 10:54:45 AM

Updated 2/17/2015 11:10:56 AM

2 Answers/Comments

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Question

Asked 2/17/2015 10:54:45 AM

Updated 2/17/2015 11:10:56 AM

2 Answers/Comments

This conversation has been flagged as incorrect.

Rating

3

In Euclidean geometry, a parallelogram is a (non self-intersecting) quadrilateral with two pairs of parallel sides.

Added 2/17/2015 11:09:21 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [2/17/2015 11:11:03 AM]

3

In Euclidean geometry, a rhombus, plural rhombi or rhombuses, is a simple (non-self-intersecting) quadrilateral all of whose four sides have the same length.

Added 2/17/2015 11:09:42 AM

This answer has been confirmed as correct and helpful.

Confirmed by yumdrea [2/17/2015 11:11:05 AM]

semicircle **Weegy:** Area formula for a semicircle: 1
Figure out the radius of the semicircle. 2
The area of the semi-circle is half the area of the corresponding circle. [ Hence, it is given by the formula:Area = [(pi)(r2)]/2 where, r is the radius of the semi-circle (or the circle) The area of a semicircle is (1/2)(pi)(r^2).
The area of a circle is (pi)(r^2)
] **User:** sphere **Weegy:** A sphere is a perfectly round geometrical object in three-dimensional space. **User:** minor arc (More)

Question

Updated 9/25/2017 5:15:35 AM

2 Answers/Comments

In mathematics (and more specifically geometry), a semicircle is a one-dimensional locus of points that forms half of a circle.

Added 9/25/2017 5:15:01 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [9/25/2017 5:46:36 AM]

Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given.
Center (8, 0), radius =
**Weegy:** In the standard equation of a circle, (x-a)^2 + (y-b)^2 = r^2, the center of the circle is (a, b) and the radius is r. **User:** Enter the equation of the line meeting the given conditions. Please put the equation in standard form.
Containing C(3, 3) and D(-3, 2)
**Weegy:** 1+-4=3 **User:** Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given.
Center (7, 5), radius = 4
**Weegy:** The equation of the circle with Center (7, 5), radius = 4 in standard form is (x - 7)^2 + (y - 5)^2 = 16. **User:** Find the distance between the given points.
W(0, 8) and X(0, 12)
Distance =
4
4 (13)
10 **Weegy:** the answer to the equation 3(w+12)**User:** Find the distance between the given points.
E(-6, 4) and F(-12, 4)
Distance =
6
8
18 **User:** Enter the equation of the line meeting the given conditions. Please put the equation in standard form.
Containing E(4, 3) and F(6, 1)
(More)

Question

Not Answered

Updated 2/18/2015 3:38:26 PM

4 Answers/Comments

The equation of the line Containing C(3, 3) and D(-3, 2) in standard form is x -6y = -15

Added 2/18/2015 3:27:23 PM

The distance between the given points W (0, 8) and X(0, 12) is distance = 4.

Added 2/18/2015 3:31:59 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/18/2015 3:36:19 PM]

The distance between the given points E(-6, 4) and F(-12, 4) is Distance = 6

Added 2/18/2015 3:33:49 PM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/18/2015 3:36:00 PM]

The equation of the line Containing E(4, 3) and F(6, 1) in standard form is x + y = 7

Added 2/18/2015 3:37:44 PM

Enter the equation of the line meeting the given conditions. Please put the equation in standard form.
Containing A(5, 3) and perpendicular to a line with slope of -2
User: Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given.
Center (-8, -3), radius = 2
User: Find the distance between the given points.
A(5, 3) and B(7, -4)
**Weegy:** -4|-4| = -4 * 4; = -16 **User:** Find the distance between the given points.
R(0, 0) and S(6, 8)
Distance =
2 7
(22)
10 **Weegy:** The answer is zero. The property is identity property of addition. This property states that any number plus 0 equals that number.
[smile]
**User:** Indicate the equation of the line meeting the given conditions. Please put the equation in standard form.
Containing A(1, 3) and B(0, 2)
(More)

Question

Not Answered

Updated 2/19/2015 4:47:20 PM

4 Answers/Comments

The equation of the circle in standard form with center (-8, -3), radius = 2 is (x + 8)^2 + (y + 3)^2 = 4.

Added 2/19/2015 4:37:57 PM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [2/19/2015 6:31:37 PM]

The distance between the given points A(5, 3) and B(7, -4) is sqrt (2^2 + 7^2) = sqrt 53

Added 2/19/2015 4:45:17 PM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [2/19/2015 6:32:30 PM]

The distance between the given points R(0, 0) and S(6, 8) is Distance = sqrt (6^2 + 8^2) = 10

Added 2/19/2015 4:46:12 PM

This answer has been confirmed as correct and helpful.

Confirmed by Andrew. [2/19/2015 6:32:56 PM]

Find the distance between the given points.
A(5, 3) and B(7, -4)
Distance =
**Weegy:** -4|-4| = -4 * 4; = - 16 **User:** Please put the equation in standard form.
Containing E(4, 3) and F(6, 1)
(More)

Question

Not Answered

Updated 2/20/2015 3:41:41 AM

2 Answers/Comments

The distance between the given points A (5 ,3) B (7 , -4) is sqrt of 53 .

distance^2 = (5 - 7)^2 + (3 + 4)^2

distance^2 = 4 + 49

distance^2 = 53

distance = sqrt of 53

distance^2 = (5 - 7)^2 + (3 + 4)^2

distance^2 = 4 + 49

distance^2 = 53

distance = sqrt of 53

Added 2/20/2015 3:37:22 AM

This answer has been confirmed as correct and helpful.

Confirmed by sujaysen [2/20/2015 7:54:44 AM]

The equation in standar form that containning E (4 , 3), F (6 , 1) is x + y = 7 .

slope = (1 - 3)/(6 - 4) = -2/2 = -1

y - 3 = -1(x - 4)

y - 3 = -x + 4

y = -x + 7

x + y = 7

slope = (1 - 3)/(6 - 4) = -2/2 = -1

y - 3 = -1(x - 4)

y - 3 = -x + 4

y = -x + 7

x + y = 7

Added 2/20/2015 3:41:41 AM

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