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The diameter of a Frisbee is 12 inches. What's the area of the Frisbee? A. 452.16 sq. in. B. 37.68 sq. in. C. 18.84 sq. in. D. 113.04 sq. in.
Area of a circle = pi x (square of the radius). Radius of the Frisbee = diameter / 2 = 12/2 = 6 inches. Area of the Frisbee = pi x (6 squared) = 3.14 x 36 = 113.04 square inches.
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Asked 1/10/2018 11:04:52 AM
Updated 116 days ago|12/26/2018 7:29:19 PM
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Area of a circle = pi x (square of the radius).
Radius of the Frisbee = diameter / 2 = 12/2 = 6 inches.
Area of the Frisbee = pi x (6 squared)
= 3.14 x 36
= 113.04 square inches.
Added 1/10/2018 12:16:04 PM
This answer has been confirmed as correct and helpful.
0
The diameter of a Frisbee is 12 inches. and the area of the Frisbee is: "113.04 sq. in".

Developing

Diameter = Radius * 2
r = 12 / 2 = 6

Area = pi * r^2
Area = 3.14 * 36
Area = 113.04

Added 116 days ago|12/26/2018 7:29:19 PM
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Solve the equation: 7x = 42. A. x = 7 B. x = – 7 C. x = – 6 D. x = 6
Weegy: 7x = 42 ; x = 42/7; x = 6 (More)
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Find the volume of a cylinder with a diameter of 10 inches and a height of 20 inches. A. 6,280 cu. in. B. 1,570 cu. in. C. 62.8 cu. in. D. 705 cu. in.
Question
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Updated 116 days ago|12/27/2018 7:53:57 AM
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Volume of a cylinder = pi x (radius squared) x height
Volume of a cylinder with a diameter of 10 inches (and therefore a radius of 10/2 = 5 inches) and a height of 20 inches is:
pi x (5 squared) x 20 cubic inches
= 3.14 x 25 x 20 cubic inches
= 1,570 cubic inches.
Added 1/10/2018 12:23:37 PM
This answer has been confirmed as correct and helpful.
The volume of a cylinder with a diameter of 10 inches and a height of 20 inches is: "1,570 cu. in".

Developing

r = diameter / 2
r = 5
V = pi * r² * h
V = 3.14 * 25 * 20
V = 1,570

Added 116 days ago|12/27/2018 7:53:57 AM
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Updated 1/10/2018 4:58:33 PM
1 Answer/Comment
Two angles are supplementary. The first angle measures 60°. The measurement of the second angle is 120°.
180° - 60° = 120°



Added 1/10/2018 4:58:33 PM
This answer has been confirmed as correct and helpful.
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Updated 1/11/2018 2:58:25 AM
1 Answer/Comment
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Added 1/11/2018 2:58:25 AM
This answer has been confirmed as correct and helpful.
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